Answer:
Option D
Explanation:
The work done can be given by the mechanical energy used to do work, i.e., Kinetic energy and potential energy provided to do the work.
In all the cases, except option D, the energy provided to do the useful work is not zero and hence work done is not zero.
In option D, the box is being pulled with constant velocity, making the acceleration zero and thus Kinetic energy of the system is zero. Hence work done in this case is zero.
Answer:
15m/s²
Explanation:
Given parameters:
Initial velocity = 10m/s
Final velocity = 40m/s
Time taken = 2s
Unknown:
Average acceleration = ?
Solution:
Acceleration is the rate of change of velocity with time;
Acceleration =
Acceleration =
= 15m/s²
Answer:

Explanation:
<u>Dimensional Analysis</u>
It's given the relation between quantities A, B, and C as follows:

and the dimensions of each variable is:



Substituting the dimensions into the relation (the coefficient is not important in dimension analysis):

Operating:


Equating the exponents:


Adding both equations:

Solving:


Answer:

It is an imaginary transformer which has no core loss, no ohmic resistance and no leakage flux. The ideal transformer has the following important characteristic. The resistance of their primary and secondary winding becomes zero. The core of the ideal transformer has infinite permeability.
<span>electric, solar, wind, and geothermal.</span>