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inessss [21]
3 years ago
12

Which unit of measurement is used in the metric system?

Mathematics
2 answers:
LuckyWell [14K]3 years ago
8 0
Kilograms is the unit of measurement used in the metric system.
tensa zangetsu [6.8K]3 years ago
4 0

Answer:

Kilograms

Step-by-step explanation:

Given that there are four measurements for weights as

tons, kilograms, Miles and gallons.

We have to find the one which is used by metric system

We know that metric system uses MKS method for units of measurement namely metre for length, kilogram for weight and seconds for time.

So here kilogram is the right answer.

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Each of Elsa's notebooks is 3/5 inches wide. If she has 30 inches of space remaining on her bookshelf, how many notebooks will f
SIZIF [17.4K]

Answer:

50 Notebooks

Step-By-Step:

First write an equation

3/5x

The x represent the number of notebooks that can fit within the shelf.

So 3/5(50)=30


6 0
3 years ago
Read 2 more answers
Find the area for this square
Irina18 [472]

Answer:

361

Step-by-step explanation:

Multiply length x width to find area. 19 x 19 = 361

5 0
2 years ago
A fair six-sided dice is rolled once. What is the probability that a 2 is shown?
VashaNatasha [74]

Answer:

C: 1/6

Step-by-step explanation:

There is one 2 on a six sided die. Therefore there is a 1/6 chance that it was a 2.

3 0
3 years ago
Read 2 more answers
For <img src="https://tex.z-dn.net/?f=e%5E%7B-x%5E2%2F2%7D" id="TexFormula1" title="e^{-x^2/2}" alt="e^{-x^2/2}" align="absmiddl
nevsk [136]
I'm assuming you're talking about the indefinite integral

\displaystyle\int e^{-x^2/2}\,\mathrm dx

and that your question is whether the substitution u=\dfrac x{\sqrt2} would work. Well, let's check it out:

u=\dfrac x{\sqrt2}\implies\mathrm du=\dfrac{\mathrm dx}{\sqrt2}
\implies\displaystyle\int e^{-x^2/2}\,\mathrm dx=\sqrt2\int e^{-(\sqrt2\,u)^2/2}\,\mathrm du
=\displaystyle\sqrt2\int e^{-u^2}\,\mathrm du

which essentially brings us to back to where we started. (The substitution only served to remove the scale factor in the exponent.)

What if we tried u=\sqrt t next? Then \mathrm du=\dfrac{\mathrm dt}{2\sqrt t}, giving

=\displaystyle\frac1{\sqrt2}\int \frac{e^{-(\sqrt t)^2}}{\sqrt t}\,\mathrm dt=\frac1{\sqrt2}\int\frac{e^{-t}}{\sqrt t}\,\mathrm dt

Next you may be tempted to try to integrate this by parts, but that will get you nowhere.

So how to deal with this integral? The answer lies in what's called the "error function" defined as

\mathrm{erf}(x)=\displaystyle\frac2{\sqrt\pi}\int_0^xe^{-t^2}\,\mathrm dt

By the fundamental theorem of calculus, taking the derivative of both sides yields

\dfrac{\mathrm d}{\mathrm dx}\mathrm{erf}(x)=\dfrac2{\sqrt\pi}e^{-x^2}

and so the antiderivative would be

\displaystyle\int e^{-x^2/2}\,\mathrm dx=\sqrt{\frac\pi2}\mathrm{erf}\left(\frac x{\sqrt2}\right)

The takeaway here is that a new function (i.e. not some combination of simpler functions like regular exponential, logarithmic, periodic, or polynomial functions) is needed to capture the antiderivative.
3 0
3 years ago
Madelyn hikes 190.5 meters up a mountain. If she is 62% of the way up, how tall is the mountain?
ira [324]

Answer:

307 Meters

Step-by-step explanation:

\frac{62}{100} = 190.5\\&#10;Cross multiply:&#10;&#10;62w = 100(190.5)&#10;&#10;Multiply 100 by 190.5:&#10;&#10;62w = 19,050&#10;&#10;Solve for w:&#10;&#10;Divide both sides by 19,050 to isolate the variable and get the answer&#10;&#10;19,050/62 = 307.25.....&#10;&#10;~ After rounding to the nearest percent, the answer is 307

8 0
2 years ago
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