The net ionic equation for the neutralization reaction involving equal molar amount amount of HNo3 and KoH is
H^+ + OH^- = H2O (l)
explanation
write the chemical equation
HNO3 (aq) + KOH(aq) = KNO3(aq) +H2O (l)
ionic eequation
H^+(aq) + NO3^- (aq) + K^+9aq) OH^-(aq) = K^+ (aq) + NO3^-(aq) + H2O(l)
cancel the spectator ions( ions which does not take place in equation ) for this case is NO3^- and No3^-
thus the net ionic is
H^+(aq) + OH^- (aq) = H2O(l)
1 mole Zn ---------- 6.02 x 10²³ atoms
0.750 moles Zn ----- ?
atoms = 0.750 * ( 6.02 x 10²³ / 1 )
= 4.515 x 10²³ atoms
hope this helps!
Moles = Mass(g) / ar
Moles of phosphorus = 0.859 / 31
= 0.0277096774
1 mole = 6.02 × 10^23
Atoms of phosphorus = 0.0277096774 × 6.02×10^23
=ans.
sorry i cant do the calculation. I dont have a calculator with me.
Answer:
Frequency of photon is 0.513×10¹⁵ s⁻¹
Explanation:
Given data:
Energy of photon = 3.4×10⁻¹⁹ J
Frequency of photon = ?
Planck's constant = 6.63 × 10⁻³⁴ Js
Solution:
Formula:
E = hf
3.4×10⁻¹⁹ J = 6.626 × 10⁻³⁴ Js × f
f = 3.4×10⁻¹⁹ J / 6.626 × 10⁻³⁴ Js
F = 0.513×10¹⁵ s⁻¹
Frequency of photon is 0.513×10¹⁵ s⁻¹.
Mass of CaCl2=11g
I hope this one is help you