Answer:
12 moles of water (H₂O)
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
6CO₂ + 6H₂O —> C₆H₁₂O₆ + 6O₂
From the balanced equation above,
6 moles of H₂O reacted to produce 1 mole of C₆H₁₂O₆.
Finally, we shall determine the number of mole of H₂O required to produce 2 moles of C₆H₁₂O₆. This can be obtained as follow:
From the balanced equation above,
6 moles of H₂O reacted to produce 1 mole of C₆H₁₂O₆.
Therefore, Xmol of H₂O will react to produce 2 moles of C₆H₁₂O₆ i.e
Xmol of H₂O = 6 × 2
Xmol of H₂O = 12 moles.
Thus, 12 moles of water (H₂O) is needed to produce 2 moles of glucose (C₆H₁₂O₆).
Calculating the number of mole of COSO4 reacted
=mass/R.F.M
R.F.M of CUSO4 is 63.54+32+64=159.6
moles is therefore 200g/159.54=1.254moles
since reacting ratio is 1:1 ,moles of Cu is also 1.254moles
mass is therefore moles x R.F.M
1.254x63.54=79.6g(answer C)
Assuming the system is an ideal gas where the intermolecular forces are very limited. In this case the ratio of the pressure to the total pressure is equal to the ratio of the moles of CO to the total number of moles. Therefore,
n/n,total = p/p,total
0.22/(0.22+0.35+0.64) = P/2.95
P = 0.536 atm
This dome-like shape forms due to the water molecules' cohesive properties, or their tendency to stick to one another. ... Water molecules at the surface (at the water-air interface) will form hydrogen bonds with their neighbors, just like water molecules deeper within the liquid.
Answer:
Kc = 9.52.
Explanation:
<em>A + 2B ⇌ C,</em>
Kc = [C]/[A][B]²,
Concentration: [A] [B] [C]
At start: 0.3 M 1.05 M 0.55 M
At equilibrium: 0.3 - x 1.05 - 2x 0.55 + x
0.14 M 1.05 - 2x 0.71 M
- For the concentration of [A]:
∵ 0.3 M - x = 0.14 M.
∴ x = 0.3 M - 0.14 M = 0.16 M.
∴ [B] at equilibrium = 1.05 - 2x = 1.05 M -2(0.16) = 0.73 M.
<em>∵ Kc = [C]/[A][B]²</em>
∴ Kc = (0.71)/(0.14)(0.73)² = 9.5166 ≅ 9.52.