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Answer:
The equilibrium concentration of 
.
The equilibrium concentration of 
.
The equilibrium concentration of 
.
Explanation:
Answer:
The equilibrium concentration of HCl is 0.01707 M.
Explanation:
Equilibrium constant of the reaction = 
Moles of 
Concentration of ![[PCl_3]=\frac{0.280 mol}{1.00 L}=0.280 M](https://tex.z-dn.net/?f=%5BPCl_3%5D%3D%5Cfrac%7B0.280%20mol%7D%7B1.00%20L%7D%3D0.280%20M)
Moles of 
Concentration of ![[Cl_2]=\frac{0.280 mol}{1.00 L}=0.280M](https://tex.z-dn.net/?f=%5BCl_2%5D%3D%5Cfrac%7B0.280%20mol%7D%7B1.00%20L%7D%3D0.280M)
Initial: 0.280 0.280 0
At eq'm: (0.280-x) (0.280-x) x
We are given:
![[PCl_3]_{eq}=(0.280-x)](https://tex.z-dn.net/?f=%5BPCl_3%5D_%7Beq%7D%3D%280.280-x%29)
![[Cl_2]_{eq}=(0.280-x)](https://tex.z-dn.net/?f=%5BCl_2%5D_%7Beq%7D%3D%280.280-x%29)
![[PCl_5]_{eq}=x](https://tex.z-dn.net/?f=%5BPCl_5%5D_%7Beq%7D%3Dx)
Calculating for 'x'. we get:
The expression of 
for above reaction follows:
![K_c=\frac{[PCl_5]}{[PCl_3][Cl_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BPCl_5%5D%7D%7B%5BPCl_3%5D%5BCl_2%5D%7D)
Putting values in above equation, we get:
On solving this quadratic equation we get:
x = 0.228, 0.344
0.228 M < 0.280 M< 0.344 M
x = 0.228 M
The equilibrium concentration of .
The equilibrium concentration of .
The equilibrium concentration of .
The pH of a solution of sulphuric acid that has hydronium ion concentration is 4.26.
<h3>How do we calculate pH?</h3>
pH of any solution is define as the negative logarithm of the concentration of H⁺ ion present in any solution, i.e.
pH = -log[H⁺]
In the question, it is given that:
Concentration of hydronium ion or H⁺ ion = 5.45×10⁻⁵ M
So, pH will be:
pH = -log(5.45×10⁻⁵)
pH = -(-4.26)
pH = 4.26
Hence required pH is 4.26.
To know more about pH, visit the below link:
brainly.com/question/172153
The temperature of the ice will go up from negative whatever to 0 Celsius. Then, it will use up energy to melt (this is what we call heat of fusion).
The temperature will then go from 0 to 100. Once it reaches 100, it will use up energy to vaporize (this is what we call heat of vaporization).
