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Alika [10]
3 years ago
8

Please look at the attachment. 25 points.

Mathematics
2 answers:
9966 [12]3 years ago
7 0
The answer is 16X^12y^19
aalyn [17]3 years ago
7 0

Answer:

16x^12 y^19

Step-by-step explanation:

I assume for this problem, you would like to simplify this problem

x^4 y^3 * x^4 y^4 * (2x y^3)^4

Note: The symbol * means multiply

= x^4 y^3 * x^4 y^4 * 16x^4 y^12

To simplify exponents that are outside of parentheses, you will have to multiply the exponent of each number inside the exponent to get the answer: (x^n)^m = x^nm

= 16x^(4+4+4) y^(3+4+12)

To simplify exponents with the same base, you will only need to add the exponents, nothing more: x^n * x^m = x^(n+m)

= 16x^12 y^19

The answer to this problem is 16x^12 y^19!

If you have any questions, please let me know! If you could mark this answer as the brainliest, I would greatly appreciate it! :D

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yulyashka [42]
I think this is find the LCM, so the answer would be 168
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3 years ago
Solve for w in the proportion.<br> W/14 = 21/42 W = ?
Nataly [62]

Answer:

W = 7

Step-by-step explanation:

1) Simplify 21/42 into 1/2

w/ 14 = 1/2

2) Multiply both sides by 14.

W = 1/2 · 14

3) Simplify

W = 14/29

4) Simplify (again)

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8 0
3 years ago
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kiruha [24]

Answer:

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Step-by-step explanation:

4 0
3 years ago
Lorne subtracted 6x3 – 2x + 3 from –3x3 + 5x2 + 4x – 7. Use the drop-down menus to identify the steps Lorne used to find the dif
Pie

Answer:

31

Step-by-step explanation:

5 0
4 years ago
Find the probability of getting a 1, 4, or 5 when you roll a standard six-sided die. Give your answer as a simplified fraction.
aivan3 [116]

The first thing to take into account is that the probability of getting any of the six numbers of the dice after rolling it is the same and that probability is 1/6. Here we are being asked about the probability of getting a 1 or a 4 or a 5. In order to find it we need to define which are our favourable cases. Favourable cases are the results we want to get when we roll the dice so getting a 1, a 4 or a 5 are all favourable cases. All the other possible outcomes are unfovourable cases: getting a 2, a 3 or a 6. So we have 3 favourable and 3 unfavourable cases. Adding them we know that the total amount of cases is 6. The probability we are looking for (i'm going to call it P) is given by these quantities I defined:

P=\frac{\text{ favourable cases}}{\text{total amount of cases}}=\frac{3}{6}=\frac{1}{2}

So the probability written as a simplified fraction is 1/2.

6 0
1 year ago
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