Helpppp please!!!!!!!!!!!

Please help! Thanks

9966 [12]

Answer:

x = +-sqrt(3) and they are the actual solutions

Step-by-step explanation:

x^2/ (2x-6) = 9/(6x-18)

get a common denominator of 6x-18

x^2/ (2x-6) * 3/3 = 9/(6x-18)

3x^2/ (6x-18) = 9/(6x-18)

since the denominators are the same, the numerators must be the same

3x^2 = 9

divide by 3 on each side

x^2 = 3

take the square root of each side

sqrt(x^2) = +-sqrt(3)

x = +-sqrt(3)

5 0

3 years ago

Consider the following hypothesis test.H0:μ1−μ2=0 Ha:μ1−μ2≠0The following results are for two independent samples taken from the

Julli [10]

Answer:

a) $z =\frac{104-106}{\sqrt{\frac{8.4^2}{80} +\frac{7.6^2}{70}}}= -1.53$

b) $p_v =2*P(z$

c) Since the p value is higher than the significance level provided we have enogh evidence to FAIL to reject the null hypothesis and we can't conclude that the true means are different at 5% of significance

Step-by-step explanation:

Information given

$\bar X_{1}= 104$ represent the mean for 1

$\bar X_{2}= 106$ represent the mean for 2

$\sigma_{1}= 8.4$ represent the population standard deviation for 1

$\sigma_{2}= 7.6$ represent the population standard deviation for 2

$n_{1}=80$ sample size for the group 1

$n_{2}=70$ sample size for the group 2

z would represent the statistic

Hypothesis to test

We want to check if the two means for this case are equal or not, the system of hypothesis would be:

H0: $\mu_{1}=\mu_{2}$

H1: $\mu_{1} \neq \mu_{2}$

The statistic would be given by:

$z =\frac{\bar X_1-\bar X_2}{\sqrt{\frac{\sigma^2_1^2}{n_1} +\frac{\sigma^2_2^2}{n_2}}}=$ (1)

Part a

Replacing we got:

$z =\frac{104-106}{\sqrt{\frac{8.4^2}{80} +\frac{7.6^2}{70}}}= -1.53$

Part b

The p value would be given by this probability:

$p_v =2*P(z$

Part c

Since the p value is higher than the significance level provided we have enogh evidence to FAIL to reject the null hypothesis and we can't conclude that the true means are different at 5% of significance

6 0

2 years ago

One of the questions in the Pew Internet & American Life Project asked adults if they used the Internet, at least occasional

murzikaleks [220]

Answer:

C

Step-by-step explanation:

i think so but it will help you

8 0

3 years ago

X = -1+y

gtnhenbr [62]