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dem82 [27]
2 years ago
7

Helpppp please!!!!!!!!!!!

Mathematics
1 answer:
madreJ [45]2 years ago
5 0
I think it’s 32 I don’t know
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Which number has a prime factorization of 2x2x5x5x7x7
Dominik [7]

Answer:

4900

Step-by-step explanation:

multiply all those numbers together

2x2x5x5x7x7 = 4900

6 0
2 years ago
The table shows conversions of pounds to ounces. A 2-column table with 4 rows. Column 1 is labeled Pounds with entries 2, 4, 6,
Readme [11.4K]

Answer:

its 96 hope this helps!

Step-by-step explanation:

it's  96 because 128-(128/8)=96

5 0
2 years ago
What is the value of minus 6 x cubed minus y squared minus 3 x y if if x = -2 and y = 4
Oksi-84 [34.3K]

Well, "minus 6 x cubed minus y squared minus 3 x y" translates to:

-6x^{2} -y^{2} -3xy

Then, if we insert the values for x and y, we get:

-6(-2)^{2} -(4)^{2} -3(-2)(4)

When we distribute and multiply:

144-16-24

And once we combine like terms:

104<em> is the answer</em>


8 0
3 years ago
Read 2 more answers
1. The probability of telesales representative making a sale on a customer call is 0.15.
Mumz [18]

Answer:

1c

 n = 33

1d

 n = 19

Step-by-step explanation:

From the question we are told that

   The  probability of telesales representative making a sale on a customer call is  p = 0.15

     The mean is  \mu  =  5

Generally the distribution of sales call  made by a  telesales representative follows a binomial distribution  

i.e  

         X  \~ \ \ \  B(n , p)

and the probability distribution function for binomial  distribution is  

      P(X = x) =  ^{n}C_x *  p^x *  (1- p)^{n-x}

Here C stands for combination hence we are going to be making use of the combination function in our calculators  

Generally the mean is mathematically represented as

     \mu =  n*  p

=>  5= n *  0.15

=>  n = 33

Generally the least number of calls that need to be made by a representative for the  probability of at least 1 sale to exceed 0.95 is mathematically represented as

      P( X \ge 1) = 1 - P( X < 1 ) > 0.95

=>    P( X \ge 1) = 1 - P( X =0 ) > 0.95

=>    P( X \ge 1) = 1 - [ ^{n}C_0 *  (0.15 )^0 *  (1- 0.15)^{n-0}] > 0.95

=>    1 - [1  *  1*  (0.85)^{n}] > 0.95

=>    [(0.85)^{n}] > 0.05

taking natural  log of both sides

n = \frac{ln(0.05)}{ln(0.85)}

=>  n = 19

3 0
2 years ago
What is the factor of 15 and 35​
Ket [755]

Answer: 5 is the GCF

Step-by-step explanation: It just is

4 0
2 years ago
Read 2 more answers
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