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dem82 [27]
3 years ago
7

Helpppp please!!!!!!!!!!!

Mathematics
1 answer:
madreJ [45]3 years ago
5 0
I think it’s 32 I don’t know
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Hurry please I need it tonight thank u so much
Lina20 [59]
It’s the 3rd option!

-5 (the bubble shaded black), the arrow going left towards -9.

Hope this helps!
4 0
2 years ago
PLEASE ANSWER + BRAINLIEST !!!!<br><br> Find the indicated sum for the arithmetic series.
schepotkina [342]
Hello there,


I believe the answer would be 17×6 - 6(9+14)(6)/2 = 102 -414 = -312 but i am not 100% Sure!! Sorry if I am wrong!

Hope I helped
8 0
3 years ago
If a polynomial function f(x) has roots 3+
irinina [24]

Answer:

Step-by-step explanation:

3+√5 is a root.

so 3-√5 is also a root

or (x-(3-√5)) is also a factor of f(x)

7 0
3 years ago
Heyaaa, can you help me out? I'm not exactly sure how to go about solving this.​
scZoUnD [109]

Answer:

$48

Step-by-step explanation:

if youre paying 9.60 in tax and the tax is 20% you have to find out what 9.60 is 20% of

and 9.60 is 20% of 48

4 0
2 years ago
Read 2 more answers
Please help me answer one of these!
babunello [35]

This seems to be referring to a particular construction of the perpendicular bisector of a segment which is not shown. Typically we set our compass needle on one endpoint of the segment and compass pencil on the other and draw the circle, and then swap endpoints and draw the other circle, then the line through the intersections of the circles is the perpendicular bisector.


There aren't any parallel lines involved in the above described construction, so I'll skip the first one.


2. Why do the circles have to be congruent ...


The perpendicular bisector is the set of points equidistant from the two endpoints of the segment. Constructing two circles of the same radius, centered on each endpoint, guarantees that the places they meet will be the same distance from both endpoints. If the radii were different the meets wouldn't be equidistant from the endpoints so wouldn't be on the perpendicular bisector.


3. ... circles of different sizes ...


[We just answered that. Let's do it again.]


Let's say we have a circle centered on each endpoint with different radii. Any point where the two circles meet will then be a different distance from one endpoint of the segment than from the other. Since the perpendicular bisector is the points that are the same distance from each endpoint, the intersection of circles with different radii isn't on it.


4. ... construct the perpendicular bisector ... a different way?


Maybe what I first described is different; there are no parallel lines.



8 0
3 years ago
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