The height of a hill, h(x), in a painting can be written as

A bond has a $12,000 face value, a 9-year maturity, and a 3.1% coupon. Find the total of the interest payments paid to the bondh

jeka57 [31]

Answer:

$15348

Step-by-step explanation:

i = prt is the simple interest equation

i = 12,000(0.031) = 372

i = 372*9 = 3348

12000+3348 = $15348

4 0

2 years ago

Solve 6 sin((π/5)x)=5 for the four smallest positive solutions

cupoosta [38]

Answer:

1.568, 3.432, 11.568, 13.432

Step-by-step explanation:

Divide equation $6\sin\left(\dfrac{\pi }{5}x\right)=5$ by 6:

$\sin\left(\dfrac{\pi }{5}x\right)=\dfrac{5}{6}.$

Then

$\dfrac{\pi }{5}x=(-1)^k\arcsin\left(\dfrac{5}{6}\right)+\pi k,\ k\in Z,$

$x=(-1)^k\dfrac{5}{\pi }\arcsin\left(\dfrac{5}{6}\right)+5k,\ k\in Z.$

Since $\arcsin\left(\dfrac{5}{6}\right)\approx 56^{\circ}\approx \dfrac{\pi }{3.2},$

four smallest positive solutions are

1. $\dfrac{5}{3.2}\approx 1.568,\ k=0;$

2. $\dfrac{-5}{3.2}+5\approx 3.432,\ k=1;$

3. $\dfrac{5}{3.2}+10\approx 11.568,\ k=2;$

4. $\dfrac{-5}{3.2}+15\approx 13.432,\ k=3.$

3 0

3 years ago

A person is watching a boat from the top of a lighthouse. The boat is approaching the lighthouse directly. When first noticed, t

7nadin3 [17]

To solve this problem, we can use the tan function to find for the distances covered.

tan θ = o / a

Where,

θ = angle = 90° - angle of depression

o = side opposite to the angle = distance of boat from lighthouse

a = side adjacent to the angle = height of lighthouse = 200 ft

When the angle of depression is 16°18', the initial distance from the lighthouse is:

o = 200 tan (90° - 16°18')

o = 683.95 ft

When the angle of depression is 48°51', the final distance from the lighthouse is:

o = 200 tan (90° - 48°51')

o = 174.78 ft

Therefore the total distance the boat travelled is:

d = 683.95 ft - 174.78 ft

4 0

3 years ago

What is the answer to this question

myrzilka [38]

2.04 divided by 4 is £0.51 per roll
4.68 divided by 9 is £0.52 per roll

4 pack is better deal because the 9 pack is more per roll

4 0

3 years ago

Read 2 more answers

PLZ HELP ASAP! ILL MARK BRAINLEST!

Sav [38]

Question 1.) Factor completely $12x^{4}+ 6x^{3}+18x^{2}$

Since $6$ divides all the three terms of the equation, so we take $6$ common out from the equation.

i.e., $6(2x^{4}+ 1x^{3}+3x^{2})$

Now, since $x^{2}$ divides all the three terms of the equation, so we take $x^{2}$ common out from the equation.

i.e., $6x^{2}(2x^{2}+ 1x+3)$

Now, this cannot be factored further as $2x^{2}+ 1x+3$ is a quadratic equation and taking out discriminant of it is:

$D = (1)^2 - 4(2)(3)\\ \ \ = 1- 24\\ \ \ = -23$

Since, the discriminant is less than zero. Therefore, the factored form of the given equation : $12x^{4}+ 6x^{3}+18x^{2}$ is : $6x^{2}(2x^{2}+ 1x+3)$

Question 2.) $7x^{3}y+ 14x^{2} y^{3} - 7x^{2}y^{2}$

Since $7$ divides all the three terms of the equation, so we take $7$ common out from the equation.

i.e., $7(x^{3}y+ 2x^{2} y^{3} - x^{2}y^{2})$

Now, since $x^{2}y$ divides all the three terms of the equation, so we take $x^{2}y$ common out from the equation.

i.e., $7x^{2}y(x+ 2y^{2} - y)$

Therefore, the factored form of the given equation : $7x^{3}y+ 14x^{2} y^{3} - 7x^{2}y^{2}$ is : $7x^{2}y(x+ 2y^{2} - y)$

Question 3.) What is the Greatest Common Factor of $x^{6}$ and $x^{3}$ ?

The Greatest Common Factor of two numbers is the biggest number which divides both the given numbers completely.

Now, for the expressions $x^{6}$ and $x^{3}$ :

Since, $x^{3}$ divides both the expressions completely and it is the biggest expression which divides both the expressions.

Therefore, $x^{3}$ is the Greatest Common Factor of $x^{6}$ and $x^{3}$

7 0

3 years ago

Read 2 more answers