This will be an obtuse angled triangle because one angle is greater than 90 degrees.
Answer:
the equation is : x²-x-12
Step-by-step explanation:
the quadratic equation is in the form of : y=ax²+bx+c
the product of the zeros is -12 and the sum is 1
b = - 1
c=-12 (product)
y=x²-x-12
check : factorize first (x+3)(x-4)=0
either x+3=0 then x=-3
or x-4=0 then x=4
-3*4=-12
-3+4=1
the equation is : x²-x-12
I'll go thru the problem and then you fill in the blanks yourself.
8 2
________
6 / 4 9 2
- 4 8
-----------------
1 2
1 2
--------------
0
We have the <span> Trigonometric Identities : </span>secx = 1/cosx; (sinx)^2 + (cosx)^2 = 1;
Then, 1 / (1-secx) = 1 / ( 1 - 1/cosx) = 1 / [(cosx - 1)/cosx] = cosx /
(cosx - 1 ) ;
Similar, 1 / (1+secx) = cosx / (1 + cosx) ;
cosx / (cosx - 1) + cosx / (1 + cosx) = [cosx(1 + cosx) + cosx (cosx - 1)] / [ (cosx - 1)(cox + 1)] =[cosx( 1 + cosx + cosx - 1 )] / [ (cosx - 1)(cox + 1)] = 2(cosx)^2 / [(cosx)^2 - (sinx)^2] = <span> 2(cosx)^2 / (-1) = - 2(cosx)^2;
</span>
The equation for the line parallel to y = −x + 2 going through the point (−3, −5) is y = -x - 8
<h3>Equation of a line</h3>
The equation of a line in point slope form is expressed as:
y - y1 = m(x-x1)
Given the equation y = -x + 2, the slope of the line parallel to the line is -1
Substitute the slope and point (-3, -5)
y -(-5) = -1(x - (-3))
y+5 = -(x + 3)
y+5 =-x - 3
y = -x - 3 - 5
y = -x - 8
Hence the equation for the line parallel to y = −x + 2 going through the point (−3, −5) is y = -x - 8
Learn more on equation of a line here: brainly.com/question/18831322
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