Answer:
Step-by-step explanation:
v=Q-P
v=(5,1,0)
u=v/(magnitude of v)=(5,1,0)/(\sqrt{5^2+1^2+0^2)
u=(5/5.09,1/5.09,0)
v=Q-P
v=(1,1,0)
u=v/(magnitude of v)=(1,1,0)/(\sqrt{1^2+1^2+0^2)
u=(1/
,1/
,0)
Answer:
8+pi/2
Step-by-step explanation:
The area of the rectangle on the bottom is 8, or 2*4. The area of the top is half (because it's a semi circle) of pi*r^2, or just 1/2 pi
B is the image of D, B is the image of E and C is the image of D
These are the only points where the image is to the left and down from the stated point.
Yes, that is the famous first Pythagorean triplet: 3²+4²=5²
or
For three lengths to be able to form a triangle, it suffices that every one of those lengths is shorter than the sum and longer than the difference of the other two.
It is enough to check just one side.
So,
3 + 4 > 5
4 - 3 < 5
Your triangle is constructible.