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Degger [83]
2 years ago
6

Solve 2x - 16 ≥ 32 - 6x.

Mathematics
1 answer:
sergij07 [2.7K]2 years ago
8 0

Hello!

\mathcal{SOLUTION:}

  • Move all the x's to the left, using the opposite operation:
  • 2x+6x-16≥32
  • Now, move all the numbers to the right, using the opposite operation:
  • 2x+6x≥32+16
  • Combine Like Terms:
  • 8x≥48
  • Divide both sides by 8:
  • x≥6

Final Answer:

x≥6

I hope it helps.

Good luck & enjoy your day!

-SnowFlake

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--------------------------  =  -------------------

cos^2 x                        1 - sinx


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cos^2 = 1-sin^2x

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1- sin^2x                       1 - sinx

factor the denominator

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--------------------------  =  -------------------

(1-sinx ) (1+sinx)                   1 - sinx

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Answer:

Step-by-step explanation:

K(0 , 4)

Midpoint M (3 , 3)

Let Point  L(x₂ , y₂)

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