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Degger [83]
2 years ago
6

Solve 2x - 16 ≥ 32 - 6x.

Mathematics
1 answer:
sergij07 [2.7K]2 years ago
8 0

Hello!

\mathcal{SOLUTION:}

  • Move all the x's to the left, using the opposite operation:
  • 2x+6x-16≥32
  • Now, move all the numbers to the right, using the opposite operation:
  • 2x+6x≥32+16
  • Combine Like Terms:
  • 8x≥48
  • Divide both sides by 8:
  • x≥6

Final Answer:

x≥6

I hope it helps.

Good luck & enjoy your day!

-SnowFlake

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Elijah trained dolphins all summer and put $5,000 of his earnings into a
s2008m [1.1K]

Answer:(a)

Step-by-step explanation:

Given

Principal amount P=\$ 5000

Rate of interest R=3.5\ \%

Time T=5\ years

Simple interest in 5 years

S.I.=\dfrac{P\times R\times T}{100}

S.I.=\dfrac{5000\times 3.5\times 5}{100}

S.I.=875\ \$

So total amount after five years=5000+875=\$ \ 5875

4 0
4 years ago
06. Kristen can run at 15km/hr and walk at 5 km/hr. She completed a 42 km marathon in 4 hours. What distance did Kristen run dur
Mrac [35]
Let x be the time she ran and y be the time she walked 

then distance ran =  25x and distance walked = 5y 

so 15x + 5y = 42

and x + y = 4

* second equn. by -5:-

-5x - 5y = -20

add this to the first equn:0

10x = 22
x = 2.2

distance she ran = 2.2 * 15  =  33 km
7 0
3 years ago
A student claims that 2i is the only imaginary root of a polynomial equation that has real coefficients. Explain the student's m
____ [38]

Answer:

The Fundamental Theorem of Algebra assures that any polynomial  f(x)=0 whose degree is n ≥1 has at least one Real or Imaginary root. So by the Theorem we have infinitely solutions, including imaginary roots ≠ 2i

Step-by-step explanation:

1) This claim is mistaken.

2) The Fundamental Theorem of Algebra assures that any polynomial  f(x)=0 whose degree is n ≥1 has at least one Real or Imaginary root. So by the Theorem we have infinitely solutions, including imaginary roots ≠ 2i with real coefficients.

a_{0}x^{n}+a_{1}x^{2}+....a_{1}x+a_{0}

For example:

3) Every time a polynomial equation, like a quadratic equation which is an univariate polynomial one, has its discriminant following this rule:

\Delta < 0\\b^{2}-4*a*c

We'll have <em>n </em>different complex roots, not necessarily 2i.

For example:

Taking 3 polynomial equations with real coefficients, with

\Delta < 0

-4x^2-x-2=0 \Rightarrow S=\left \{ x'=-\frac{1}{8}-i\frac{\sqrt{31}}{8},\:x''=-\frac{1}{8}+i\frac{\sqrt{31}}{8} \right \}\\-x^2-x-8=0 \Rightarrow S=\left\{\quad x'=-\frac{1}{2}-i\frac{\sqrt{31}}{2},\:x''=-\frac{1}{2}+i\frac{\sqrt{31}}{2} \right \}\\x^2-x+30=0\Rightarrow S=\left \{ x'=\frac{1}{2}+i\frac{\sqrt{119}}{2},\:x''=\frac{1}{2}-i\frac{\sqrt{119}}{2} \right \}\\(...)

2.2) For other Polynomial equations with real coefficients we can see other complex roots ≠ 2i. In this one we have also -2i

x^5\:-\:x^4\:+\:x^3\:-\:x^2\:-\:12x\:+\:12=0 \Rightarrow S=\left \{ x_{1}=1,\:x_{2}=-\sqrt{3},\:x_{3}=\sqrt{3},\:x_{4}=2i,\:x_{5}=-2i \right \}\\

4 0
3 years ago
23,802 divided by 34 <br> HALP
lilavasa [31]

Answer:

700.058824 but rounded to the nearest tenth it would be 700.1.

Step-by-step explanation:

8 0
4 years ago
PLS HELP ME!!!! I WILL MARK U!!!!!<br><br> MATH!!!!
erica [24]

Answer:

-38

Step-by-step explanation:

y=2

z=-17

yz-y^2

(2)(-17)-(2)^2

-34-4

-38

4 0
3 years ago
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