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tino4ka555 [31]
3 years ago
6

The actual distance between two villages is 120 kilometers. On a map of the area, 0.5 centimeter represents 2 kilometers.

Mathematics
2 answers:
inn [45]3 years ago
5 0

Answer:

what he said

Step-by-step explanation:

saveliy_v [14]3 years ago
3 0

Answer:

30 centimeters

Step-by-step explanation:

I hope this helps

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2.6x0.47 I KNOW THE ANSWER JUST PLS SHOW YOUR WORK​
KiRa [710]

Answer:

just show that you moved the decimal 2 times

Step-by-step explanation:

4 0
3 years ago
Solve for z. 8z − 4 = 7z
aleksandr82 [10.1K]

8z − 4 = 7z

move 8z to the other side

sign changes from +8z to -8z

8z-8z-4=7z-8z

-4= 7z-8z

-4= -z

mutiply both sides by -1 to get +z

(-4)(-1)= (-z)(-1)

Answer:

z= 4

5 0
3 years ago
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Charlie has 468 onions he puts 12 in each bag. He sells each bag for 8$ a bag.
antoniya [11.8K]

Answer:

$312

Step-by-step explanation:

468/12

12 * 8

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3 years ago
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A line passes through $A(1,1)$ and $B(100,1000)$. How many other points with integer coordinates are on the line and strictly be
jonny [76]

Answer:

98

Step-by-step explanation:

Integers are whole numbers or opposite of whole numbers.

The slope is 1.

How?

Change of y is 100-1=99.

Change of x is 100-1=99.

The slope is 99/99=1 or 1/1.

So if we start at (1,1) and we rise 1 and run 1 right, we get (2,2).

If we do that again from (2,2) we get (3,3).

Following the pattern of going up 1 and right from each new location discovered we get all the of these points:

Start (1,1)

(2,2)

(3,3)

(4,4)

(5,5)

(6,6)

....

(96,96)

(97,97)

(98,98)

(99,99)

end (100,100)

So we just need to count all the numbers from 2 to 99.

99-2+1

97+1

98

7 0
2 years ago
A 50-gallon rain barrel is filled to capacity. It drains at a rate of 10 gallons per minute. Write an equation to show how much
makvit [3.9K]

Answer:

The quantity of water drain after x min is 50 (0.9)^{x}  

Step-by-step explanation:

Given as :

Total capacity of rain barrel = 50 gallon

The rate of drain = 10 gallon per minutes

Let The quantity of water drain after x min = y

Now, according to question

The quantity of water drain after x min = Initial quantity of water ×  (1-\dfrac{\textrm rate}{100})^{\textrm time}

I.e The quantity of water drain after x min = 50 gallon ×  (1-\dfrac{\textrm 10}{100})^{\textrm x}

or,  The quantity of water drain after x min = 50 gallon × (0.9)^{x}

Hence the quantity of water drain after x min is 50 (0.9)^{x}  Answer

4 0
3 years ago
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