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3 years ago

12

They randomly survey 50 students about how much money they spend on lunch each day. What is the expected value for a student to

spend on lunch each day?

1 answer:

siniylev [52]3 years ago

3 0

2$ for public 3-4$ for private

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If t1 = 4, s1 = 5, and s2 = 2, determine the value of t2.

Len [333]

Answer:

t2=8/5

Step-by-step explanation:

using this formula

t1/s1 =t2/s2

4/5=t2/2

cross multiply

5t2=8

t2=8/5

8 0

2 years ago

I will mark you brainiest if you can answer this

Cerrena [4.2K]

Answer:

i can not see the picture

Step-by-step explanation:

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3 years ago

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Which statement about determining the quotient 12÷14 is true?

san4es73 [151]

Answer:

2.beacuse 3 x 4= 12, 12 divided by 4 is 3

6 0

3 years ago

You bike 1 mile the first day of your training, 1.3 miles the second day, 1.9 miles the third day, and 3.1 miles the fourth d

JulsSmile [24]

Answer:

19.9 miles

Step-by-step explanation:

In this problem we have:

$d_1=1 mi$ is the distance travelled during the 1st day

$d_2=1.3 mi$ is the distance travelled during the 2nd day

$d_3=1.9 mi$ is the distance travelled during the 3rd day

$d_4=3.1 mi$ is the distance travelled during the 4th day

We notice that the difference between the distance travelled on the (n+1)-th day and the distance travelled on the n-th day doubles every day. In fact:

$d_2-d_1=0.3\\d_3-d_2=2\cdot 0.3 = 0.6\\d_4-d_3=2\cdot 0.6 = 1.2$

Which can be rewritten using the general formula:

$d_{n+1}-d_n=2(d_n-d_{n-1})$

This means that

$d_{n+1}=d_n+2(d_n-d_{n-1})$

By applying this formula recursively, we can find the 7th term, which is the distance travelled on the 7th day:

$d_1=1\\d_2=1.3\\d_3=1.9\\d_4=3.1\\d_5=3.1+2\cdot 1.2=5.5\\d_6=5.5+2\cdot 2.4=10.3\\d_7=10.3+2\cdot 4.8=19.9 mi$

So, the distance travelled on the 7th day is 19.9 miles.

7 0

4 years ago

A 2 W 1) 115* 54° 2v+1°

larisa86 [58]

The answer is: V = 29

5 0

2 years ago