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guapka [62]
2 years ago
7

Donna reads a book at a rate of 20 chapters per hour.

Mathematics
2 answers:
mart [117]2 years ago
8 0

Answer:

20/1=20 1 hour read one book

Step-by-step explanation:

4 chapter read in 4 hour because 1 chapter read in one gour

Studentka2010 [4]2 years ago
5 0

Answer:

80

Step-by-step explanation:

When working with rates, multiplication is very useful. Rate questions will give a specific rate and then a time period. They often ask, based on the rate, what can be achieved in the given time period.

The question says that if Donna can read 20 chapters in 1 hour, how many chapters can she read in 4 hours. To solve this, you can multiply 20*4; this will show how many chapters she reads in the given time period.

Since 20*4=80, she must read 80 chapters in 4 hours.

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−2(2x+3)≤26<br><br>-<br><br>2<br><br>2<br><br>x<br><br>+<br><br>3<br><br>≤<br><br>26<br><br>?
SashulF [63]

\huge \boxed{\mathbb{QUESTION} \downarrow}

- 2 ( 2 x + 3 ) \leq 26.

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

- 2 ( 2 x + 3 ) \leq 26

Divide both sides by -2. We know that since 2 is negative, it'll be < (less than) 0. So, the direction of inequality will change.

2x+3\geq \frac{26}{-2}  \\

Divide 26 by -2..we'll get the answer as -13.

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Now, subtract 3 from both the sides.

2x\geq -13-3

Subtracting -13 by 3..we'll get the answer as -16.

2x\geq -16

Divide both sides by 2. We know that since 2 is positive, the direction of inequality will remain the same.

x\geq \frac{-16}{2}  \\

Divide -16 by 2..we'll get the answer as -8.

\huge \boxed{ \boxed{ \bf \: x\geq -8 }}

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find the number of possible combinations choose one of three books and one of eight CDs to bring on a bus trip
SVEN [57.7K]
There is a possibility of 24 combinations I believe
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erma4kov [3.2K]
$72.

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3 years ago
Find the missing sides, and give the simplified form of the square root
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Answer:

in the pics

Step-by-step explanation:

In case you are wondering, I used the pythagorean theorem. If you want to learn how to use it I suggest you google it, there are plenty of sites that explain how to use it.

If you have any questions about the way I solved it, don't hesitate to ask me in the comments below :)

7 0
3 years ago
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