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guapka [62]
2 years ago
7

Donna reads a book at a rate of 20 chapters per hour.

Mathematics
2 answers:
mart [117]2 years ago
8 0

Answer:

20/1=20 1 hour read one book

Step-by-step explanation:

4 chapter read in 4 hour because 1 chapter read in one gour

Studentka2010 [4]2 years ago
5 0

Answer:

80

Step-by-step explanation:

When working with rates, multiplication is very useful. Rate questions will give a specific rate and then a time period. They often ask, based on the rate, what can be achieved in the given time period.

The question says that if Donna can read 20 chapters in 1 hour, how many chapters can she read in 4 hours. To solve this, you can multiply 20*4; this will show how many chapters she reads in the given time period.

Since 20*4=80, she must read 80 chapters in 4 hours.

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Ashley received a $24 discount on a radio she bought for $98.00. What is the percent of discount she saved?
katrin [286]

Answer:

24.49

Step-by-step explanation:

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2 years ago
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Jonathan’s class has 30 boys. Of the students in his class, 60% are girls. How many girls are in Jonathan’s class?
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Answer: 45

Step-by-step explanation:


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Caleb has 550 candy bars and eats 2 a day. Robert has 850 candy bars and eats 6
Alex17521 [72]

Answer:

B. 550 - 2x > 850 - 6x

Step-by-step explanation:

7 0
3 years ago
One Solution<br>no solution <br>infinitely many solutions<br>3x + 9 + 4x + x =<br>_x+_​
ss7ja [257]
All you need to do it combine like terms.

3x + 9 + 4x + x

(3x + 4x + x) + 9

8x + 9

i hope this was helpful for you!
8 0
3 years ago
Stock A ‘s returns have a standard deviation of 0.5, and stock B’s returns have standard deviation of 0.6.The correlation coeffi
galben [10]

Answer:

The variance of the profile is 0.2179.

Step-by-step explanation:

We are given the following in the question:

\sigma_A = 0.5\\\sigma_B = 0.6\\\rho_{A,B} = 0.5\\w_A = 70\% = 0.7\\w_B = 30\% = 0.3

Variance of portfolio is given by:

w_A^2\sigma_A^2 +w_B^2\sigma_B^2 + 2w_Aw_BCov_{A,B}

Cov_{A,B} = \rho_{A,B} \times \sigma_A \times \sigma_B \\=0.5\times 0.5 \times 0.6\\=0.15

Putting values, we get,

w_A^2\sigma_A^2 +w_B^2\sigma_B^2 + 2w_Aw_BCov_{A,B}\\=(0.7)^2(0.5)^2 + (.3)^2(0.6)^2 + 2(0.7)(0.3)(0.15)\\=0.2179

Thus, the variance of the profile is 0.2179.

4 0
3 years ago
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