Question:
If a sample of 2 hammer is selected
(a) find the probability that all in the sample are defective.
(b) find the probability that none in the sample are defective.
Answer:
a
b
Step-by-step explanation:
Given
--- hammers
--- selection
This will be treated as selection without replacement. So, 1 will be subtracted from subsequent probabilities
Solving (a): Probability that both selection are defective.
For two selections, the probability that all are defective is:
Solving (b): Probability that none are defective.
The probability that a selection is not defective is:
For two selections, the probability that all are not defective is:
Percent increase
find increase first
10500 to 11300
11300-10500=800
so
percent increase
change/original
origianal=10500
change=800
800/10500=8/105=0.0761
percent means parts out of 100
0.0761/1 times 100/100=7.61/100=7.61%
rond 7.61% to tenth or to 7.6%
7.6%
Step-by-step explanation:
PRIMERO CONVIERTES MINUTOS A HORAS
15 MIN = 0.25 h
LUEGO CON LA ECUACIÓN DE GALILEI:
<em>x</em> = 6.5 mi/0.25 h = 26 mi
Answer: 0.03855
Step-by-step explanation:
Given :A population of skiers has a distribution of weights with mean 190 pounds and standard deviation 40 pounds.
Its maximum safe load is 10000 pounds.
Let X denotes the weight of 50 people.
As per given ,
Population mean weight of 50 people =
Standard deviation of 50 people
Then , the probability its maximum safe load will be exceeded =
Thus , the probability its maximum safe load will be exceeded = 0.03855