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noname [10]
2 years ago
11

Two planets with the same mass and atmospheric conditions orbit a single star. Planet A is closer to the star than Planet B. Whi

ch description explains the expected average surface temperatures of Planets A and B?
Planet B is expected to be cooler than Planet A.

Planet B is expected to be hotter than Planet A.

Both planets are the same temperature.

Distance has no influence on a planet's average surface temperature.
Physics
1 answer:
8_murik_8 [283]2 years ago
3 0

Answer:

is not this one Planet B is expected to be hotter than Planet A.

Explanation:

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A wire of cross-sectional area 5.00 106 m2 has a resistance of 1.75 O. What is the resistance of a wire of the same material and
MakcuM [25]

Answer:

the resistance of the second wire is 1 ohm.

Explanation:

Given;

cross sectional area of the first wire, A₁ = 5.00 x 10⁶ m²

resistance of the first wire, R₁ = 1.75 ohms

cross sectional area of the second wire, A₂ = 8.75 x 10⁶ m²

resistance of the second wire, R₂ = ?

The resistance of a wire is given as;

R ∝ \frac{L}{A}

Since the length of the two wires is constant

R₁A₁ = R₂A₂

R_2 = \frac{R_1A_1}{A_2} \\\\R_2 = \frac{1.75\  \times \ 5.00\times 10^6}{8.75\times 10^6} \\\\R_2 = 1 \ ohm

Therefore, the resistance of the second wire is 1 ohm.

6 0
3 years ago
The gravity tractor, is a proposed spacecraft that will fly close to an asteroid whose trajectory threatens to impact the Earth.
Crazy boy [7]

Answer:

F_g=461lb_f

Explanation:

First calculate the mass of the asteroid. To do so, you need to find the volume and know the density of iron.

If r = d/2 = 645ft, then:

V = \frac{4}{3} \pi r^3

V = \frac{4}{3} \pi r^3\\V = 1.124\times10^{9}ft^3\delta_{iron}=m/V=491lb/ft^3m=V\times\delta=5.519\times10^{11}lb

In order to find force, use Newton's universal law of gravitation:

F_g=G\frac{m_1m_2}{d^2}

Where,

G= the gravitational constant:

G= 1.068846 \times10^{-9} ft^3 lb^{-1} s^{-2}

F_g=461lb_f

4 0
3 years ago
A ball is thrown into the air with an upward velocity of 32 feet per second. Its height, h, in feet after t
LekaFEV [45]
Differentiate the expression, to obtain expression for velocity. Set velocity to 0, this when max height is reached. Obtain the tmax from that expression.

<span>h(t) = –16t² + 32t + 6
</span><span>h'(t) = –32t² + 32
0 = </span>–32t² + 32
t max= 1

hmax = <span> –16(1)² + 32(1) + 6
hmax = 22

Therefore, first option is the correct answer.</span>
8 0
3 years ago
Read 2 more answers
20 kg who is running at a speed of 4.0 m/s jumps onto a stationary sled of mass 5.0 kg on a frozen lake. the speed at which the
Step2247 [10]

Here we can use momentum conservation as there is no external force on sled and child while he jump on sled

by momentum conservation equation

m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v{2f}

20*4 + 5*0 = 20*v + 5 *v

since sled and child both moves with same speed so here they both will have same final speed "v"

by solving above equation we will have

25 v = 80

v = 3.2 m/s

So they will move together with speed 3.2 m/s

6 0
3 years ago
50 Joules of work in 25 seconds. How much power did she use?
Lorico [155]

P(W) = E(J) / t(s)

50/25=2

3 0
3 years ago
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