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MaRussiya [10]
3 years ago
7

Of orbital radius, orbital velocity, orbital circumference, or radial area swept through, which of these stays constant accordin

g to one of Kepler’s Laws?
a. orbital distance
b. radial area swept through
c. none of these
d. orbital velocity
Physics
1 answer:
kow [346]3 years ago
5 0

Answer:

dyow

Explanation:

sorrrey

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Matter that has a fixed composition is a ________. Which is formed by_______.
Alenkasestr [34]
A) Pure substances, Chemical changes

8 0
3 years ago
Which of these equations will you used to find the final velocity if the initial
Svetach [21]

Answer:

2.77 would be the answer for this

5 0
3 years ago
A sensor is used to monitor the performance of a nuclear reactor. The sensor accu-rately reflects the state of the reactor with
Helen [10]

Answer:

The probability of an incorrect report is found to be 0.03 or 3%.

Explanation:

We will get an incorrect report in both the cases of false alarm or missing excessive radiation. Since, both are mutually exclusive events. Therefore, the probability of both events to occur simultaneously will be 0. Thus, the probability of an incorrect report will be the sum of the probability of false alarm and the probability of a missing radiation.

P (False Alarm) = 0.02

P (Missing Radiation) = 0.01

P(Incorrect Report) = P (False Alarm) + P(Missing Radiation)

P (Incorrect Report) = 0.02 +0.01

P(Incorrect Report) = 0.03 = 3%

7 0
3 years ago
Please help me!!! ASAP 10 points for first to answer.
strojnjashka [21]
See the image above :)

7 0
3 years ago
A steel rod is pulled in tension along its center axis (the axial direction) with a stress that is less than the yield strength.
Kamila [148]

Answer:

D. Axial stress divided by axial strain

Explanation:

 Lets take rod is pulled by force P

Stress σ = P/A

We know that

σ = ε E

E=  Lets take rod is pulled by force P

Stress σ = P/A

We know that

σ = ε E

σ=Axial stress

ε  =Axial Strain = ΔL/L

E= σ/ε

E= Axial stress/Axial Strain

So the modulus of elasticity  is the ratio of axial stress to axial strain.

σ=Axial stress

ε  =Axial Strain = ΔL/L

E= σ/ε

E= Axial stress/Axial Strain

So the modulus of elasticity  is the ratio of axial stress to axial strain.

The option D is correct.

6 0
3 years ago
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