Question

Two stationary point charges of +60.0 uC and +50.0 uC exert a repulsive force

Answer 1

Answer:

The value is $r = 0.39279 \ m$

Explanation:

From the question we are told that

     The first point charge is $q_1 = 60.0 \mu C = 60 *10^{-6} \ C$

      The second point charge is  $q_2 = 50 \mu C = 50 *10^{-6} \ C$

     The repulsive force exerted is  $F = 175 \ N$

Generally the repulsive force  exerted is mathematically represented as

     $F = \frac{k * q_1 * q_2 }{r^2}$

Here k is the coulomb constant with a value  $k = 9*10^{9}\ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.$

So

       $r = \sqrt{\frac{ k * q_1 * q_2 }{F} }$

=>    $r = \sqrt{\frac{ 9*10^9 * 60 *10^{-6} * 50 *10^{-6}}{175} }$

=>    $r = 0.39279 \ m$