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3 years ago

Two stationary point charges of +60.0 uC and +50.0 uC exert a repulsive force

Physics

1 answer:

joja [24]3 years ago

8 0

Answer:

The value is $r = 0.39279 \ m$

Explanation:

From the question we are told that

The first point charge is $q_1 = 60.0 \mu C = 60 *10^{-6} \ C$

The second point charge is $q_2 = 50 \mu C = 50 *10^{-6} \ C$

The repulsive force exerted is $F = 175 \ N$

Generally the repulsive force exerted is mathematically represented as

$F = \frac{k * q_1 * q_2 }{r^2}$

Here k is the coulomb constant with a value $k = 9*10^{9}\ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.$

$r = \sqrt{\frac{ k * q_1 * q_2 }{F} }$

=> $r = \sqrt{\frac{ 9*10^9 * 60 *10^{-6} * 50 *10^{-6}}{175} }$

=> $r = 0.39279 \ m$

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