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2 years ago

12

What is the name of an instruction that interrupts a program being executed and requests a service from the operating system

Computers and Technology

1 answer:

tresset_1 [31]2 years ago

7 0

“Interrupt” is what I think the answer is

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Oxnard Casualty wants to ensure that their e-mail server has 99.98 percent reliability. They will use several independent server

sattari [20]

Answer:

The smallest number of servers required is 3 servers

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Explanation:

Given

$Reliability = 99.98\%$

$Individual Servers = 95\%$

Required

Minimum number of servers needed

Let p represent the probability that a server is reliable and the probability that it wont be reliable be represented with q

Such that

$p = 95\%\\$

It should be noted that probabilities always add up to 1;

So,

$p + q = 1$ '

Subtract p from both sides

$p - p + q = 1 - p$

$q = 1 - p$

Substitute $p = 95\%\\$

$q = 1 - 95\%$

Convert % to fraction

$q = 1 - \frac{95}{100}$

Convert fraction to decimal

$q = 1 - 0.95$

$q = 0.05$

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<em>To get an expression for one server</em>

The probabilities of 1 servers having 99.98% reliability is as follows;

$p = 99.98\%$

Recall that probabilities always add up to 1;

So,

$p + q = 1$

Subtract q from both sides

$p + q - q = 1 - q$

$p = 1 - q$

So,

$p = 1 - q = 99.98\%$

$1 - q = 99.98\%$

Let the number of servers be represented with n

The above expression becomes

$1 - q^n = 99.98\%$

Convert percent to fraction

$1 - q^n = \frac{9998}{10000}$

Convert fraction to decimal

$1 - q^n = 0.9998$

Add $q^n$ to both sides

$1 - q^n + q^n= 0.9998 + q^n$

$1 = 0.9998 + q^n$

Subtract 0.9998 from both sides

$1 - 0.9998 = 0.9998 - 0.9998 + q^n$

$1 - 0.9998 = q^n$

$0.0002 = q^n$

Recall that $q = 0.05$

So, the expression becomes

$0.0002 = 0.05^n$

Take Log of both sides

$Log(0.0002) = Log(0.05^n)$

From laws of logarithm $Loga^b = bLoga$

So,

$Log(0.0002) = Log(0.05^n)$ becomes

$Log(0.0002) = nLog(0.05)$

Divide both sides by $Log0.05$

$\frac{Log(0.0002)}{Log(0.05)} = \frac{nLog(0.05)}{Log(0.05)}$

$\frac{Log(0.0002)}{Log(0.05)} = n$

$n = \frac{Log(0.0002)}{Log(0.05)}$

$n = \frac{-3.69897000434}{-1.30102999566}$

$n = 2.84310893421$

$n = 3 (Approximated)$

<em>Hence, the smallest number of servers required is 3 servers</em>

6 0

3 years ago

What is a good monitor for console gaming? (Any price)

likoan [24]

Answer:

I personally use a alienware

Explanation:

7 0

3 years ago

Read 2 more answers

"Your supervisor has asked you to modify the AMOUNT column in the ORDERS table. He wants the column to be configured to accept a

vesna_86 [32]

Answer:

ALTER TABLE orders

MODIFY (amount DEFAULT 250)

Explanation:

ALTER TABLE statement is used to modify "amount" column in the existing "orders" table
MODIFY (amount DEFAULT 250) is used to set the default value 250 of the "amount" column.

Therefore if the supervisor wants the amount column to be configured to accept a default value of 250, then "ALTER TABLE orders MODIFY (amount DEFAULT 250) " statement should be issued.

5 0

3 years ago

Meenakshi has created a presentation of six slides. The slides have the same background, but s wants to change the background of

sdas [7]

Ans:- Using Background Styles button present in Background group on the Design tab.

5 0

2 years ago

For this assignment, you will create flowchart using Flow gorithm and Pseudocode for the following program example: Hunter Cell

larisa86 [58]

Answer:

The pseudocode is as given below while the flowchart is attached.

Explanation:

The pseudocode is as follows

input customer name, number of texts

Set Basic bill=5 $;

if the number of texts is less than or equal to 60

Extra Charge=0;

If the number of texts is greater than 60 and less than 200

number of texts b/w 60 and 200 =number of texts-60;

Extra Charge=0.1*(number of texts b/w 60 and 200);

else If the number of texts is greater than 200

number of texts beyond 200 =number of texts-200;

Extra Charge=0.25*(number of texts beyond 200)+0.1*(200-60);

Display Customer Name

Total Bill=Basic bill+Extra Charge;

Total Bill after Tax=Total Bill*1.12;

3 0

3 years ago