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diamong [38]
2 years ago
9

PLS HELP ME ASAP ILL GIVE 50 POINTS AND BRAINIEST TO WHOEVER ANSWER CORRECTLY AND SHOWS THEIR WORK PLAS I NEED HELP ON THIS

Mathematics
1 answer:
iogann1982 [59]2 years ago
6 0
Part A: 0.85p=c
Now here p represents the number of pounds for toys, so let’s say if there’s two pounds of toys you multiply by 0.85 which is the cost of shipping for one toy

Part B
It will be almost the same type of equation u just change the number so
0.05p=c
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Marsha's class is planting 120 trees as part of a community volunteer project. The class plants pine trees and oak trees in a ra
Ivanshal [37]

Answer:

pine:oak=3:1

pine=3/4*120

pine=90 trees

Step-by-step explanation:

6 0
3 years ago
How many milliliters of 0.30% sugar solution must you add to 75mL of 4% sugar solution to get a 0.50% sugar solution?
hammer [34]
Based on the given data above, the equation below has been generated,
(X mL)(0.003) + 75 mL (0.04) = 0.005 (75 + X); X being the amount in mL of the sugar solution, by further simplification of the generated equation, it can be said that 1312.5 mL of 0.30% sugar solution should be added to 75 mL of 4% solution to come up with a 0.5% sugar solution.
4 0
3 years ago
Read 2 more answers
30 – 2x = 2(3x + 3) using PEMDAS
soldi70 [24.7K]

Answer:

Hey there! First you start with parenthesis! So distribute the 2 to 3x. There you get 6x. Now distribute to the 3. You get 6. Now you move the 2x over to the right side. Getting 30=4x+6.. Now move the 6 over to the 30. You get 24=4x..Now you divide, getting the answer 6! Hope this helps...

Answer is 6

8 0
4 years ago
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Male and female high school students reported how many hours they worked each week in summer jobs. The data is represented in th
mihalych1998 [28]

Question:

1. The females worked less than the males, and the female median is close to Q1.

2. There is a high data value that causes the data set to be asymmetrical for the males.

3. There are significant outliers at the high ends of both the males and the females.

4. Both graphs have the required quartiles.

Answer:

The correct option is;

1. The females worked less than  the males, and the female median is close to Q1

Step-by-step explanation:

Based on the given data, we have;

For males

Minimum = 0

Q1 = 1

Median or Q2 = 20

Q3 = 25

Maximum = 50

For females;

Minimum = 0

Q1 = 5

Median or Q2 = 6

Q3 = 10

Maximum = 18

Therefore, the values of data that affect the statistical measures of spread and center are that

The females worked less than the males as such the statistical data for the females have less variability than the males in terms of interquartile range

Also the female median is very close to Q1, therefore it affects the definition of a measure of center.

5 0
4 years ago
If x+3/3 = y+2/ 2 , then x/3 = _____.​
iren [92.7K]

the question is not so clear

is it (x+3)/3 or what you have written is correct

Step-by-step explanation:

4 0
3 years ago
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