All categories

2 years ago

Use synthetic substitution to find f (2) and f (-1) for the function. f (x) = x3 – x2 – 2x + 3

Mathematics

1 answer:

kotegsom [21]2 years ago

3 0

Answer:

f(2)=7

f(-1)=+1

Step-by-step explanation:

f (2)= 2³-2²+3 =8-4+3=7

f (-1)= (-1)³-(-1)²+3= -1- (+1) +3= -1-1+3=+1

You might be interested in

10 POINTS IDENTIFY THE SLOPE, Y-INTERCEPT AND GRAPH.<br> 1. Y = 2x + 3<br> 2. Y = 3/4x - 2

Alenkasestr [34]

Answer for problem 1: slope = 2, y intercept = 3

Answer for problem 2: slope = 3/4, y intercept = -2

Explanation:

Both equations are in the form y = mx+b. This is known as slope intercept form. This is because we can read off the values of the slope and y intercept very quickly. We have y = 2x+3 match up with y = mx+b. The m is the slope and b is the y intercept. So m = 2 and b = 3 for this equation. A similar situation happens with the other equation as well. It might help to rewrite the second equation into y = (3/4)x + (-2).

4 0

2 years ago

Read 2 more answers

Please write the equation and solve:

Olegator [25]

A nonmember would have to go skating 11 times a year and a member would have to go skating 12 times a year.

They each paid $110.

I hope this is correct!

Good luck:)

3 0

3 years ago

8x-5y=21 simultaneous linear equation<br>2x+9y=-5

olya-2409 [2.1K]

Answer:

$x=2$ and $y=-1$

Step-by-step explanation:

If two equations are given, we can solve one of the equation in terms of single variable and put it in the other equation which will further give the value of x and y.

For the given equations:

$8x-5y=21$ Equation:1

$2x+9y=-5$ Equation:2

Solving equation multiply equation 2 with 4 on both the sides

$8x+36y=-20$ Equation 3

Subtracting Equation:3 from Equation:1

$8x-5y-(8x+36y)=21-(-20)\\8x-5y-8x-36y=21+20\\-41y=41\\y=-1$

Putting value of 'y' in Equation:2 which will give the value of x

$2x+9y=-5\\2x+9(-1)=-5\\2x-9=-5\\2x=4\\x=2$

8 0

3 years ago

PLEASE HELP!

Wittaler [7]

Answer:

See below

Step-by-step explanation:

Use the formulae directly

For a cone, with base radius = r and height = h, here are the related formula

$\textrm{Slant height l} = \sqrt{r^2 + h^2}$ (1)

$\textrm{Lateral surface area} = \pi r l$

$\textrm {Base area} = \pi r^2$

$\textrm { Total Surface Area SA} = \textrm{Base Area + Lateral Area} = \pi r^2 + \pi rl = \pi r(r + l)$ (2)

$\textrm{Volume V = } (1/3) \pi r^2h$ (3)

Therefore directly plugging in the numbers in the above equations:

Note:

l = slant height in cm
SA = total surface area in sqcm
V = Volume in cubic cm

Figure(a)

r = 4, h = 8

$\textrm{l} = \sqrt{4^2 + 8^2} =\sqrt{80} = 8.944 \\\textrm{SA} = 4\pi(4 + 8.944) = 4\pi(12.944) = 162.66\\\textrm{V} = (1/3)\pi(4^2)(8) = 134.04$