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nignag [31]
3 years ago
9

Please give explanation

Mathematics
1 answer:
cricket20 [7]3 years ago
3 0

rewrite the equation as


x/3 + 1 = y/2 + 1


Subtract one from both sides:


x/3 = y/2.


and boom, there’s your answer.

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Consider the function f(x)=3x^3-5x^2-88x+60-5 is a root of f(x). Find all of the roots of f(x)
Tom [10]
If -5 is a root then f(x) is divisible by x + 5

The quotient from this division is 3x^2 -20x +12
Factoring this:-

= 3x^2 - 18x - 2x + 12
= 3x(x - 6) - 2(x - 6)
= (3x - 2)(x - 6)
So 2 more roots are 2/3 and 6
All the roots are -5 , 2/3 and 6.  Answer
8 0
4 years ago
-4 (r + 2) = 4 (2 - 2r)
Nady [450]

Answer:

r=4

Step-by-step explanation:

Let's solve your equation step-by-step.

−4(r+2)=4(2−2r)

Step 1: Simplify both sides of the equation.

−4(r+2)=4(2−2r)

(−4)(r)+(−4)(2)=(4)(2)+(4)(−2r)(Distribute)

−4r+−8=8+−8r

−4r−8=−8r+8

Step 2: Add 8r to both sides.

−4r−8+8r=−8r+8+8r

4r−8=8

Step 3: Add 8 to both sides.

4r−8+8=8+8

4r=16

Step 4: Divide both sides by 4.

4r

4

=

16

4

r=4

Answer:

r=4

3 0
3 years ago
Find the transition matrix from B to B'. B = {(-1,2), (3, 4)), B' = {(1, 0), (0, 1)} STEP 1: Begin by forming the following matr
8_murik_8 [283]

Answer:  The required matrix is

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Step-by-step explanation:  We are given to find the transition matrix from the bases B to B' as given below :

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Let us consider two real numbers a, b such that

(-1,2)=a(1,0)+b(0,1)\\\\\Rightarrow (-1,2)=(a,b)\\\\\Rightarrow a=-1,b=2.

Again, let us consider reals c and d such that

(3,4)=c(1,0)+d(0,1)\\\\\Rightarrow (3,4)=(c,d)\\\\\Rightarrow c=3,d=4.

Therefore, the transition matrix is given by

T=\left[\begin{array}{ccc}-1&3\\2&4\end{array}\right] .

Thus, the required matrix is

T=\left[\begin{array}{ccc}-1&3\\2&4\end{array}\right] .

7 0
3 years ago
-4-(-1) answer the question
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Answer:

-3

Step-by-step explanation:

Since you are subtracting a negative, it turns positive so it will be.

-4+1

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4 0
3 years ago
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To find the ratio of centimeters to meters you need to divide 66 by 33 to get 2.
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3 years ago
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