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Aleonysh [2.5K]

3 years ago

13

Consider the function f(x)=3x^3-5x^2-88x+60-5 is a root of f(x). Find all of the roots of f(x)

1 answer:

Tom [10]3 years ago

8 0

If -5 is a root then f(x) is divisible by x + 5

The quotient from this division is 3x^2 -20x +12
Factoring this:-

= 3x^2 - 18x - 2x + 12
= 3x(x - 6) - 2(x - 6)
= (3x - 2)(x - 6)
So 2 more roots are 2/3 and 6
All the roots are -5 , 2/3 and 6. Answer

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Find the equation of the line passing through point (4,2) and perpendicular to AB

Setler [38]

Answer:

a. -⅓

b. 3

c. y = 3x - 10

Step-by-step explanation:

a. Gradient of line AB:

A(1, 3), B(7, 1)

$Gradient = \frac{y_2 - y_1}{x_2 - x_1} = \frac{1 - 3}{7 - 1} = \frac{-2}{6} = -\frac{1}{3}$

Gradient (m) = -⅓

b. The of the line that is perpendicular to line AB would be the negative reciprocal of the gradient of line AB.

Thus, the negative reciprocal of -⅓ = 3

Gradient of the line perpendicular to line AB = 3

c. Equation of the line that passes through (4, 2) and is perpendicular to line AB:

We can write the equation using the point-slope form equation, y - b = m(x - a), where,

(a, b) represents a point on the line, and,

m = gradient/slope

We know that the gradient/slope (m) = 3

Also, a point, (a, b) = (4, 2).

Therefore, substitute a = 4, b = 2, and m = 3 into y - b = m(x - a)

Thus:

y - 2 = 3(x - 4)

y - 2 = 3x - 12

Add 2 to both sides

y = 3x - 12 + 2

y = 3x - 10

5 0

2 years ago

Find the domain of the function f of x equals the square root of the quantity three x minus two.

katovenus [111]

F(x)=(3x-2)^0.5
C.x is greater than or equal to two thirds

8 0

2 years ago

Guys, Can you please help me with these questions

MakcuM [25]

Answer:

a) $w^{13} x^{5} y^{6}$

b) $\frac{x}{3y^{6} }$

Step-by-step explanation:

a) $(w^{2} xy^{3} )^{2}(w^{3}x )^{3}$

1. Distribute the second power (2) outside the first pair of parenthesis:

$(w^{2(2)} x^{2} y^{3(2)} )$

= $w^{4} x^{2} y^{6} (w^{3}x )^{3}$

2. Distribute the third power (3) outside the second pair of parenthesis:

$(w^{3(3)} x^{3} )$

= $w^{4} x^{2} y^{6} w^{9} x^{3}$

3. Combine like terms:

$w^{13} x^{5} y^{6}$

--------------------------------------------

b) $\frac{2x^{2} y^{5} }{6xy^{11} }$

1. Factor the number 6 (= 2 · 3):

$\frac{2x^{2} y^{5} }{2(3)xy^{11} }$

2. Cancel the common factor (2):

$\frac{x^{2} y^{5} }{3xy^{11} }$

3. Cancel out $xy^{5}$ in the numerator an denominator:

$\frac{x}{3y^{6} }$

hope this helps!

4 0

2 years ago

While shopping, Lucinda spent $48. If the amount she spent was 15% of her savings, how much savings did she

Dima020 [189]

(48/x)=(15/100) so x=320

3 0

2 years ago

Where is 0.5 on the graph? I have to do ( 0.5, 4)

schepotkina [342]

Answer:

It would be between the 0 and the 1 on the horizontal line

0.5 is where the blue dot is, then for 0.5 , 4 just go up 4 from there

3 0

2 years ago