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snow_tiger [21]
3 years ago
10

The complicated molecules that make up living things usually contain

Chemistry
2 answers:
katrin [286]3 years ago
8 0

The carbon atom is capable of forming four covalent bonds in combination with other elements as hydrogen, oxygen, nitrogen, sulfur, phosphorous and halogens. The compounds formed are called organic molecules which because of the nature of the chemical bond are stable compounds.

Adding an amino group -NH₂ and a carboxylic group -COOH to a carbon chain containing carbon and hydrogen we form amino acids. Condensation of amino acids will form peptides and further proteins, which are chemical molecules from which living things are made.

Carbon is the backbone of the molecules from which life is made.

Tema [17]3 years ago
3 0

Answer;

A. Carbon can form four strong covalent bonds.

Explanation;

Carbon can form up to 4 covalent bonds, and it can form reasonably strong bonds with nitrogen, oxygen, and other heteroatoms.

Carbon also has an almost unique ability to catenate: to form long chains with

C − C linkages, and along the chain there can be regions of different reactivity (by the presence of functional groups).

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An object exerts force of 500 n and sits on an area of 4.5m X 1.5m. Calculate the amount of pressure exerted by the object in to
vlabodo [156]

4.5 times 1.5

divide by 500n

5 0
3 years ago
When a 0.235-g sample of benzoic acid is combusted in a bomb calorimeter, the temperature rises 1.643 ∘C . When a 0.275-g sample
andrew-mc [135]

Answer : The heat of combustion per mole of caffeine at constant volume is 76197.18 kJ/mole

Explanation :

First we have to calculate the specific heat calorimeter.

Formula used :

Q=m\times c\times \Delta T

where,

Q = heat of combustion of benzoic acid = 26.38 kJ/g = 26380 J/g

m = mass of benzoic acid = 0.235 g

c = specific heat of calorimeter = ?

\Delta T = change in temperature = 1.643^oC

Now put all the given value in the above formula, we get:

26380J/g=0.235g\times c\times 1.643^oC

c=68323.38J/^oC

Thus, the specific heat of calorimeter is 68323.38J/^oC

Now we have to calculate the heat of combustion of caffeine.

Formula used :

Q=c\times \Delta T

where,

Q = heat of combustion of caffeine = ?

c = specific heat of calorimeter = 68323.38J/^oC

\Delta T = change in temperature = 1.584^oC

Now put all the given value in the above formula, we get:

Q=68323.38J/^oC\times 1.584^oC

Q=108224.23J=108.2kJ

Now we have to calculate the moles of caffeine.

\text{Moles of caffeine}=\frac{\text{Mass of caffeine}}{\text{Molar mass of caffeine}}

Mass of caffeine = 0.275 g

Molar mass of caffeine = 194.19 g/mole

\text{Moles of caffeine}=\frac{0.275g}{194.19g/mole}=0.00142mol

Now we have to calculate the heat of combustion per mole of caffeine at constant volume.

\text{Heat of combustion per mole of caffeine}=\frac{108.2kJ}{0.00142mol}=76197.18kJ/mole

Therefore, the heat of combustion per mole of caffeine at constant volume is 76197.18 kJ/mole

4 0
3 years ago
Determine the empirical formula of a compound containing 40. 6 grams of carbon, 5. 1 grams of hydrogen, and 54. 2 grams of oxyge
zavuch27 [327]

The empirical formula is C₂H₃O₂

<h3>What is Empirical formula of a compound ?</h3>

The empirical formula is the simplest whole number ratio of elements present in a compound.

The total molar mass of the compound is 118.084 g/mol.

mass of Carbon present = 40.6

mass of Hydrogen present = 5.1 grams

mass of Oxygen present = 2 grams

Moles of C = 40.6/12 = 3.38

Moles of H = 5.1/1.008 = 5

Moles of Oxygen = 54.2/15.999 = 3.38

Ratio of Moles of C to Oxygen is 1 : 1

Ratio of Moles of C to H is 1/1.5

Multiplying each mole fraction by 2

The empirical formula is C₂H₃O₂

To know more about Empirical Formula

brainly.com/question/14044066

#SPJ1

5 0
2 years ago
Which statement about common descent is correct?
ludmilkaskok [199]
Hey, What are the options can’t see anything!
7 0
3 years ago
Match each molecular formula to the corresponding empirical formula.
lawyer [7]

Explanation:

C₄H₈O₂                      C₂H₄O

C₄H₁₂O₄                       CH₃O

C₂H₁₀O₂                      CH₅O

The empirical formula is that which expresses the composition of a compound in the simplest whole number ratio of the atoms of the different elements that makes up a compound.

The molecular formula is the true formula of the compound. It expresses the actual number of moles of atoms of the different elements present in a molecule of the compound.

C₄H₈O₂                      C₂H₄O

4: 8 : 2 divided by 2 gives 2: 4 : 1

C₄H₁₂O₄                       CH₃O

4: 12: 4  divided by 3 gives 1: 3: 1

C₂H₁₀O₂                      CH₅O

2: 10: 2 divided by 2 gives 1: 5: 1

learn more:

Empirical formula brainly.com/question/2774727

#learnwithBrainly

5 0
4 years ago
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