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Margaret [11]
3 years ago
14

Which set of changes does not involve breaking or forming chemilcal bonds

Chemistry
1 answer:
sineoko [7]3 years ago
6 0
<h2><u>Answer:</u></h2>

It wasn't an adjustment in the condition of issue on the grounds that the vitality in the can did not change. Additionally, since this was a physical change, the atoms in the can are as yet similar particles. No synthetic bonds were made or broken.  You added enough vitality to make a stage change from strong to fluid.  

The main changes recorded which don't include framing or breaking substance bonds would bubble and liquefying. Bubbling and liquefying are physical changes as opposed to synthetic changes, so no new items are shaped.

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Need help with 14 and 16 pls asap!! this is my friends test and im taking it tomorrow!!
marin [14]

Answer:

Q14: 17,140 g = 17.14 kg.

Q16: 504 J.

Explanation:

<u><em>Q14:</em></u>

  • To solve this problem, we can use the relation:

<em>Q = m.c.ΔT,</em>

where, Q is the amount of heat absorbed by ice (Q = 3600 x 10³ J).

m is the mass of the ice (m = ??? g).

c is the specific heat of the ice (c of ice = 2.1 J/g.°C).

ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = 100.0°C - 0.0°C = 100.0°C).

∵ Q = m.c.ΔT

∴ (3600 x 10³ J) = m.(2.1 J/g.°C).(100.0°C)

∴ m = (3600 x 10³ J)/(2.1 J/g.°C).(100.0°C) = 17,140 g = 17.14 kg.

<u><em>Q16:</em></u>

  • To solve this problem, we can use the relation:

<em>Q = m.c.ΔT,</em>

where, Q is the amount of heat absorbed by ice (Q = ??? J).

m is the mass of the ice (m = 12.0 g).

c is the specific heat of the ice (c of ice = 2.1 J/g.°C).

ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = 0.0°C - (-20.0°C) = 20.0°C).

∴ Q = m.c.ΔT = (12.0 g)(2.1 J/g.°C)(20.0°C) = 504 J.

6 0
3 years ago
Energy cannot be created or destroyed. Does the statement describe a scientific law?
LekaFEV [45]
Yes, the law of thermodynamics, or Law of Conservation of Energy
3 0
3 years ago
Complete the table below by deciding whether a precipitate forms when aqueous solutions A and B are mixed. If a precipitate will
stiks02 [169]

The reaction between copper II chloride and sodium sulfide as well as lead II nitrate and potassium sulfate both produce precipitates.

The solubility of a substance in water is in accordance with the solubility rules.  It is possible that a solid product may be formed when two aqueous solutions are mixed together. That solid product is referred to as a precipitate.

Now, we will consider each reaction individually to decode whether or not a precipitate is possible.

  • In the first reaction, we have; CuCl2(aq) + Na2S(aq) ---->CuS(s) + 2NaCl(aq). A precipitate (CuS) is formed.
  • In the second reaction, Pb(NO3)2(aq) + 2KNO3(aq) ----> PbSO4(s) + KNO3(aq), a precipitate PbSO4 is formed
  • In the third reaction, NH4Br(aq) + NaOH(aq) ----->NH3(g)  + NaBr(aq) + H2O(l), a precipitate is not formed here.

Learn more: brainly.com/question/11969651

6 0
3 years ago
Chlorine is a halogen and has 7 valence electrons, which is represented by crosses on the left
makkiz [27]

There are 2 electrons in the overlapping region.

Chlorine is the second member of the halogen group which are form of family of elements that resemble one another very closely.

The electronic configuration of chlorine shows the arrangement of chlorine electrons within it's atom.

At the outer most shell of the atom is seven electrons, therefore requires only one electron each to attain the octet arrangement.

The overlapping of the orbitals indicates the chemical bond formed by sharing of electrons between atoms called covalent bonding.

To complete it's outer most shell, it will need to share electron with another chlorine atom.

Therefore, there are 2 electrons in the overlapping region.

Learn more here:

brainly.com/question/16396974

3 0
2 years ago
What occurs during interphase? (Select all that apply.)
murzikaleks [220]

Answer:

during interphase the cells start to grow

6 0
2 years ago
Read 2 more answers
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