I would say the object will float because the density of water is 999.99kg/m which is slightly less than 1g but still more than the object.
Answer:
We draw line AB which is perpendicular to the 14 cm side
Since Angle C is 60 degrees that makes angle CAB = 30 degrees
Triangle CAB is a 30 60 90 triangle so line CB is half the hypotenuse or 5 cm
Line BD equals 9 cm
Line AB^2 = 10^2 - 5^2 = 75
Line AD^2 = AB^2 + BD^2
Line AD^2 = 75 + 81
Line AD^2 = 156
Line AD = 12.4899959968
Line AB = Sqr root (75) = 8.6602540378
Angle D = arc sine (8.6602540378 / 12.4899959968)
Angle D = 43.898 degrees
Angle A = 180 - 60 - 43.898 = 76.102 degrees
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Actually this could have been done a little easier by using the Law of Cosines and then the Law of Sines, but I just thought I'd show another way to solve this.
Step-by-step explanation:
Answer:
Step-by-step explanation:
The graph of this function is that of a parabola that opens down (due to the negative coefficient of t^2). The axis of symmetry is
-b -100
x = --------- = ----------- = 50/16 = 25/8.
2a 2(-16)
The y value of the vertex is h(25/8) = -16(25/8)^2 + 100(25/8) + 10, or 166/25.
The largest value this function can take on is 166/25. Thus, the range is
(-infinity, 166/25).
Since the given function is a polynomial, the domain consists of all real numbers.
Answer:
A.
Step-by-step explanation:
A quadrilateral inscribed in a circle has its opposite angles adding up to 180°
So
<NOP + <M = 180
4x+8x-24 = 180
12x = 180+24
12x = 204
Dividing both sides by 12
x = 17
<NOP = 4(17)
= 68°