KE= 0.5(m)(v^2)
KE= 250,000 J
Answer:
The pressure difference is 25.8kPa while the force exerted on the window by air pressure is 3.02 kN
Explanation:
Using the Bernoulli's equation

Here
- Pin-Pout is the pressure difference which is to be calculated.
- ρ is the density of air whose value is 1.29 kg/m^3
- vin is the velocity of air inside which is 0 m/s
- vout is the velocity of air outside which is 200 m/s
Substituting values in the above equation yields

So the pressure difference is 25.8kPa.
As force is given by

Here
- ΔP is the pressure difference calculated above
- A is the area of the window given as

Now force is

So the force exerted on the window by air pressure is 3.02 kN
Answer:
I'm not really sure but I think it is
four
<span>more lines = a lot of electrons returning back to ground state from same level</span>