Question

A 16.0 g bullet is moving to the right with speed 250 m/s when it hits a target and travels an additional 22.6 cm into the target. What are the magnitude (in N) and direction of the stopping force acting on the bullet

Answer 1

Answer:

The magnitude will be "2212 N".

Explanation:

The given values are:

Initial speed, u = 250 m/s

Final speed, v = 0

Mass, m = 16.0 = 0.016 kg

Distance, d = 22.6 cm

On converting cm into m, we get

d = 0.226 m

As we know,

⇒  $v^2-u^2=-2ad$

⇒  $a=\frac{v^2-u^2}{-2d}$

On putting the estimated values, we get

⇒    $=\frac{(0)^2-(250)^2}{-2\times 0.226}$

⇒    $=\frac{0-62500}{-0.452}$

⇒    $=13,8276 \ m/s^2$

Now,

Force, $F=ma$

On putting values, we get

⇒            $=0.016\times 138276$

⇒            $=2212 \ N$ (magnitude)