Heat is best defined as

Which statement best describes the difference between acceleration and velocity?

Sloan [31]

C. is the answer because acceleration is the change in velocity in time while velocity is speed with a direction

8 0

3 years ago

A merry-go-round makes one complete revolution in 5.3 s. A 48.5 kg child sits on the horizontal floor of the merry-go-round 2.7

Marianna [84]

Answer:183.94 N

Explanation:

Given

Time Period $T=5.3 s$

mass of child $m=48.5 kg$

Radius $r=2.7 m$

Velocity $v=\frac{2\pi \cdot r}{T}$

$v=\frac{2\pi \cdot 2.7}{5.3}$

$v=3.20 m/s$

Now Centripetal Force will be Balanced by Frictional Force

Centripetal Force $F_c=m\cdot \frac{v^2}{r}$

$F_c=48.5\cdot \frac{3.2^2}{2.7}$

$F_c=183.94 N$

therefore Friction Force is 183.94 N

4 0

3 years ago

A ball is thrown directly upward from a height of 3 ft with an initial velocity of 28 ft/sec. the function s(t)equalsminus16ts

borishaifa [10]

Answer:

$t = 0.875 s$

$s_{max} = 15.25 ft$

Explanation:

Position of the ball as a function of time is given as

$s(t) = s_o + v_y t + \frac{1}{2}at^2$

$s(t) = 3 + 28 t - 16 t^2$

now we know that when ball will attain maximum height then the differentiation of the position with respect to time will become zero

so we have

$\frac{ds}{dt} = 0$

$0 = 0 + 28 - 32 t$

$t = 0.875 s$

now the maximum height is given as

$s_{max} = 3 + 28(0.875) - 16(0.875)^2$

$s_{max} = 15.25 ft$

4 0

3 years ago

A solenoid with 465 turns has a length of 8.00 cm and a cross-sectional area of 3.10 ✕ 10−9 m2. Find the solenoid's inductance a

hoa [83]

The solenoid's inductance and the average emf around the solenoid if the current changes from +3.50 A to −3.50 A in 7.83 ✕ 10−3 s will be 1.01 ×10⁻⁸ H and 9.02 × 10⁻² V.

<h3>What is a solenoid?</h3>

A coil of wire that carries an electric current is a solenoid. A solenoid is an electromagnet formed by a helical coil of wire.

Which generates a magnetic field when an electric current is passed through the coil.

A solenoid is a form of coil that produces a magnetic field when the electric current is passed through it. A solenoid is created when a conductive wire is used to make a loop.

Given data;

Turns ,N = 465

Length,L= 8.00 cm

Cross-sectional area,A = 3.10 ✕ 10−9 m2.

Solenoid's inductance, L=?

The average emf around the solenoid, E=?

Time of flow,t= 7.83 ✕ 10−3 s

Current changes from +3.50 A to −3.50 A

The inductance of the solenoid is found as;

$\rm L = \frac{\mu_0 AN^2}{L} \\\\ \rm L = \frac{4 \times \pi \times 10^{-7}\times 3.0 \times 10^{-9} \times (465)^2 }{8.00 \times 10^{-2}} \\\\ L= 1.01 \times 10^{-8} \ H$

The average emf around the solenoid is found as;

$\rm e = L \frac{I_2-I_1}{t} \\\\ \rm e = 1.01 \times 10^{-8} \times \frac{3.50-(-3.50)}{7.83 \times 10^{-3}} \\\\ e =9.02 \times 10^{-12} \ V$

Hence, the solenoid's inductance will be 1.01× 10⁻⁸ H.

To learn more about the solenoid refer;

brainly.com/question/16015159

#SPJ1

3 0

2 years ago

A 120 N force, directed at an angle θ above a horizontal floor, is applied to a 28.0 kg chair sitting on the floor. If θ = 0°, w

ivanzaharov [21]

Answer:

See explanation

Explanation:

Given:-

- The applied force Fa = 120 N

- The angle made with Fa and horizontal = θ

- The mass of chair m = 28.0 kg

Find:-

a) θ = 0 , the horizontal component Fh of the applied force and (b) the magnitude FN of the normal force of the floor on the chair?

If θ = 34.0°, what are (c)Fh and (d)FN?

If θ = 65.0°, what are (e)Fh and (f)FN?

Now assume that the coefficient of static friction between chair and floor is 0.410. What is the maximum force of static friction on the chair if θ is (g) 0°, (h)34.0°, and (i)65.0°?

Solution:-

- We will consider the applied force (Fa) and develop a general expression for Fh as function of θ. Using Trigonometry we have:

Fh = Fa*cos ( θ )

- The normal contact force (N) can be expressed similarly by applying equilibrium conditions on the chair in vertical direction.

N - mg - Fa*sin(θ) = 0

N = m*g + Fa*sin(θ)

For, θ = 0:

Fh = Fa*cos(0) = Fa

Fh = 120 N

N = (28*9.81) + 120*0

N = 274.68 N

For, θ = 34.0:

Fh = Fa*cos(34) = (120)*(0.82903)

Fh = 99.5 N

N = (28*9.81) + 120*sin(34)

N = 341.8 N

For, θ = 65.0:

Fh = Fa*cos(65) = (120)*(0.42261)

Fh = 50.7 N

N = (28*9.81) + 120*sin(65)

N = 383.4 N

- The maximum frictional force (Ff) is given by the following expression:

Ff = N*us

Where, us = coefficient of static friction = 0.41

For, θ = 0:

Ff = (274.68)*(0.41)

Ff = 112.62 N

For, θ = 34:

Ff = (341.8)*(0.41)

Ff = 140.13 N

For, θ = 65:

Ff = (383.4)*(0.41)

Ff = 157.2 N

5 0

3 years ago