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2 years ago

WHO EVER HELPS ME WITH THIS GETS BRAINLIST NO JOKE

Chemistry

1 answer:

galben [10]2 years ago

4 0

Answer

for number 1 RAIN. Rain is drops of water from clouds. Heavy/ constant/ steady/pouring rain or Downpour is a lot of rain in a short...

SNOW. Snow means atmospheric water vapor frozen into ice crystals and falling in light white flakes or lying on the...

SUN. Blazing means very bright and hot. ... Bright means full of light.

number 2 WEATHER MAPS indicate atmospheric conditions above a large portion of the Earth’s surface. Meteorologists use weather maps to forecast the weather. A HYGROMETER measures the water vapor content of air or humidity. A WEATHER BALLOON measures weather conditions higher up in the atmosphere.

number 3 A climate is an average weather in a given area over a period of time. The weather, on the other hand, can change drastically in a matter of hours. Changing the world takes thousands of years. It is, however, complex and has been growing at an alarming rate in recent years.

Weather refers to how the environment behaves, mostly in terms of its impacts on life and human habits. Temperature, humidity, precipitation, brightness, cloudiness, visibility, wind, and atmospheric pressure all are factors that influence the weather on a daily basis.

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MATCH

almond37 [142]

I wanna say it would be 1 would be A 2 would be C 3 would be D 4 would be B and 5 would be E

hope this helps

6 0

3 years ago

Read 2 more answers

The equilibrium constant, K, for the following reaction is 1.80x102 at 698 K. 2HI(9) =H2(g) +129) An equilibrium mixture of the

Mrrafil [7]

Explanation:

The equilibrium constant of the reaction = $K_c=1.80\times 10^{-2}$

Initial concentration of HI = 0.311 M

After addition 0.174 mol of HI(g)

Concentration of HI added = $\frac{0.174 mol}{1 L}=0.174 M$

New concentration of HI = 0.311 M + 0.174 M = 0.485 M

$2HI\rightleftharpoons H_2+I_2$

Initial concentration:

0.311 M $4.71\times 10^{-2} M$ $4.71\times 10^{-2} M$

At equilibrium:

(0.485 M - x) $(4.71\times 10^{-2} M+x)$ $(4.71\times 10^{-2} M+x)$

$K_{eq}=\frac{[H_2][I_2]}{[HI]^2}$

$1.80\times 10^{-2}=\frac{(4.71\times 10^{-2} M+x)\times (4.71\times 10^{-2} M+x)}{ (0.485 M-x)^2}$

$\sqrt{1.80\times 10^{-2}}=\frac{(4.71\times 10^{-2} M+x)}{ (0.485 M-x)}$

$0.1342=\frac{(4.71\times 10^{-2} M+x)}{(0.485 M-x)}$

$0.065087 M-0.1342x=4.71\times 10^{-2} M+x$

$0.065087 M-4.71\times 10^{-2} M=1.1342x$

$x=\frac{0.017987 M}{1.3142}=0.01586 M$

Equilibrium concentrations:

$[HI]=0.485 M-x = 0.485 M - 0.01586 M= 0.46914 M$

$[H_2]=[I_2]=4.71\times 10^{-2} M+x=4.71\times 10^{-2} M+0.01586 M$

$[H_2]=[I_2]=0.06296 M$

3 0

3 years ago

When the ionic compound ammonium chloride, NH 4 Cl, , dissolves in water, it breaks into one ammonium ion, NHt^ 1+ , one chlorid

Arada [10]

Answer:

0.400 moles

Explanation:

Well, you know that one mole of ammonium chloride,

NH 4 Cl , dissociates completely in aqueous solution to form one mole of ammonium cations,

NH + 4 , and one mole of chloride anions, Cl − .

3 0

3 years ago

What do I scan to confirm that a book is relevant and valuable as a source

Elden [556K]

It's genre. Look for something either on a final or starting page near the cover, and check to look if it's non fiction, or anything else that could prove it as reliable.

7 0

3 years ago

13.3 g of benzene (C6H6) is dissolved in 282 g of carbon tetrachloride. What is the molal concentration of benzene in this solut

Verizon [17]

Answer:

0.605 molal

Explanation:

molality is the amount of solute in a particular mass of solvent.

lets calculate the amount of benzene solute.

mass of benzene= 13.3g

molar mass of C6H6= 12*6 +1*6 =72+7=78g/mol

amount of benzene= mass/molar mass

=13.3/78

=0.1705mol

molality= amount of solute/mass of solvent in kg

mass of solvent=282g=0.282kg

molality = 0.1705/0.282

=0.605 molal

6 0

3 years ago