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stealth61 [152]
2 years ago
5

27. Which of the following molecules are chiral?(EXTRA CREDIT I. 2-Chlorobutane II. 3-Bromopentane ?. 1-Bromo-2-methylpropene IV

. 2-Bromo-3-methylbutane A) I,? B) I, IV C) ?, 111
Chemistry
1 answer:
igor_vitrenko [27]2 years ago
5 0

2-Chlorobutane, 2-Bromo-3-methylbutane are chiral .

chiral condition - a compound is said to be chiral if it is surrounded by 4 different groups

I,IV are chiral

II,III are achiral

Molecular types with non-superposable mirror images are known as chiral molecules. The existence of an asymmetric carbon atom in a molecule is the characteristic that most frequently contributes to chirality. When referring to an object that cannot be superposed on its mirror counterpart, the adjective "chiral" is generally employed.

A corkscrew, golf clubs, scissors, and other chiral items all have a "handedness." Thus, one can get scissors and golf clubs that are designed for either hand. Gloves and shoes are also sold in pairs, a right and a left.

learn more about chiral molecules here:

brainly.com/question/28095208

#SPJ4

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Explanation:

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what explanation can you give for the fact that considerably different speeds of diffusion were reported for methyl salicylate?​
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Explanation:

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Calculate the solubility at 25°c of cubr in pure water and in a 0.0030m cobr2 solution. you'll find ksp data in the aleks data t
Reil [10]

Answer:

the solubility at 25°c of cubr in pure water = 0.011 g/L

The solubility at 25°c of cubr  in a 0.0030m cobr2 solution = 0.00014 g/L

Explanation:

Step 1: Data given

Ksp of CuBr = 6.27 × 10^-9

Molar mass CuBr = 143.45 g/mol

Step 2: Calculate the solubility at 25°c of cubr in pure water

Ksp = [Cu+][Br-]

The initial concentration

[Cu+] = 0M

[Br-] = 0M

The concentration at the equilibrium

[Cu+] = X M

[Br-] = X M

Ksp =6.27 * 10^-9 =  X * X = X²

S = 7.9 *10^-5 mol /l  

7.9 * 10^-5 mol/L * 143.45 g/mol = 0.011 g/L

Step 3: Calculate the solubility at 25°c of cubr  in a 0.0030m cobr2 solution.

The balanced equation:

CoBr2(aq) → Co^2+(aq) + 2 Br⁻(aq)

For 1 mol CoBr2 we'll have 1 mol Co^2+ and 2 moles Br-

For 0.0030 M CoBr2 we'll have 0.0030 M Co^2+ and 0.0060 M Br-

The initial concentration

[Cu+] = 0M

[Br-] = 0.0060 M

At the equilibrium

[Cu+] = X

[Br-] = 0.0060 + X

Ksp = 6.27 * 10^-9 = X * (0.0060+X)

6.27 *10^-9 = 0.0060 X + X²

X = 1.0 * 10^-6 mol/L

1.0 * 10^-6 mol/L * 143.45 g/mol = 0.00014 g/L

6 0
3 years ago
Calculate the pH of a solution prepared by dissolving 0.147 moles of acetic acid and 0.405 moles of sodium acetate in water suff
Roman55 [17]

Answer:

pH = 5.19

Explanation:

Mixture of acetic acid with sodium acetate produce a buffer (Buffer is defined as the mixture of a weak acid with its conjugate base and vice versa). The pH of the buffer can be determined using Henderson-Hasselbalch equation:

pH = pKa + log₁₀ [A⁻] / [HA]

<em>Where pKa is -log Ka = 4.75; [A⁻] is the concentration of conjugate base (Acetate ion) and [HA] is molar concentration of the weak acid.</em>

-You can use moles of the compounds rather than its concentrations, that is:

[HA] = 0.147 moles

[A⁻] = 0.405 moles

Replacing in H-H equation:

pH = 4.75 + log₁₀ [0.405] / [0.147]

<h3>pH = 5.19</h3>
7 0
3 years ago
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