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andrew11 [14]
3 years ago
6

PLEASE HELP !

Chemistry
1 answer:
mario62 [17]3 years ago
4 0

Answer:

2L of water.

Explanation:

To know the volume of water to be added to the initial solution, first let us calculate the volume of the final solution. This is illustrated below:

Data obtained from the question:

Initial volume (V1) = 2L

Initial concentration (C1) = 6mol/L

Final concentration (C2) = 3mol/L

Final volume (V2) =?

Using the dilution formula, we can obtain the final volume of the stock as follow:

C1V1 =C2V2

6 x 2 = 3 x V2

Divide both side by 3

V2 = (6 x 2)/3

V2 = 4L.

The final volume of the solution is 4L.

To obtain the volume of water added, we shall determine the change in the volume of the solution. This is illustrated below:

Initial volume (V1) = 2L

Final volume (V2) = 4L

Change in volume = V2 – V1 = 4 – 2 = 2L.

Therefore, 2L of water must be added to the initial solution.

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Calculate the molarity of 29.9 g of MgS in 911 mL of solution??
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0.58 is the molarity of 29.9 g of MgS in 911 mL of solution.

Define the molarity of a solution.

Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution. Molarity is also known as the molar concentration of a solution.

Given data:

Volume of solution = 911 mL=0.911L

Given the mass of  MgS = 29.9 g

Molar mass of MgS = 56.38 g/mol

Moles of MgS = 0.5303299042

Molality = \frac{Moles \;solute}{Volume \;of \;solution \;in \;litre}

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Molality = 0.5821403998=0.58

Hence,  0.58 is the molarity of 29.9 g of MgS in 911 mL of solution.

Learn more about Molarity here:

brainly.com/question/2817451

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