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Triss [41]
4 years ago
15

HELP ASAP PLEASE!!!!

Chemistry
2 answers:
Sunny_sXe [5.5K]4 years ago
8 0

Answer 1 KOH is a strong base
Travka [436]4 years ago
4 0

1 because OH is a base and H+ would be an acid

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Nguyên tố X có hai đồng vị, đồng vị thứ nhất có số khối 35 chiếm 75%. Nguyên tử khối trung bình của X là 35,5. Đồng vị thứ hai c
BlackZzzverrR [31]

Answer:

C

Explanation:

  • Why (C) because it is the correct answer
  • about my answer i how it correct
4 0
3 years ago
Calculate H3O+ when OH- is 2*10 -8
klio [65]
Relationship between [H3O+] and [OH-] is:

[H3O+] X [OH-] = 1.00 X10^-14

Rearranging gives:
[H3O+] = 1.0X10^-14 / [OH-]

Just plug in and calculate your [H3O+] values
6 0
4 years ago
What color do you get if you mix red and blue light?
andrezito [222]

Answer:

Purple light.

Yellow light.

Explanation:

5 0
3 years ago
Read 2 more answers
Given the two half-reactions, what must be done in the next step before the reaction can be balanced? Au3+ --> Au I- --> I
Artyom0805 [142]

Answer:

The balance equation is

2Au^{+3} + 6I^{-} → 2Au + 3I_{2}

Explanation:

first, we have to make sure that the atoms are balanced

Au^{+3} → Au^{}

2I^{-} → I_{2}

then we proceed to balance charges of each half-reaction

Au^{+3} + 3e^{-} → Au^{}

2I^{-} → I_{2} + 2e^{-}

Now we multiply the half-reactions to match the number of electrons in each one

(Au^{+3} + 3e^{-} → Au^{})x2

            (2I^{-} → I_{2} + 2e^{-})x3

and now we do the sum of the half-reactions

2Au^{+3} + 6e^{-} → 2Au^{}

              6I^{-} → 3I_{2} + 6e^{-}

2Au^{+3} + 6I^{-} → 2Au + 3I_{2}

note: the only atom that needed to be balanced was I

3 0
4 years ago
Read 2 more answers
why does an aluminum horseshoe bend but not break when a blacksmith pounds it into shape with a hammer?
riadik2000 [5.3K]

Answer:

it's because aluminium is a ductile material

8 0
3 years ago
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