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2 years ago

Fifty Points and Brainliest! Select all that have a proportional relationship:

Mathematics

1 answer:

klasskru [66]2 years ago

5 0

Answer:

B and D both have a proportional relationship

Step-by-step explanation:

Please give brainliest

<u>Your Welcome</u> :)

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I WILL GIVE BRAINLIEST TO THE FIRST PERSON!A spinner has 8 equal-sized sections. The probability that the spinner will stop abov

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The chances of it spinning on blue is likely

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2 years ago

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An environment engineer measures the amount ( by weight) of particulate pollution in air samples ( of a certain volume ) collect

Serggg [28]

Answer:

$k = 1$

$P(x > 3y) = \frac{2}{3}$

Step-by-step explanation:

Given

$f \left(x,y \right) = \left{ \begin{array} { l l } { k , } & { 0 \leq x} \leq 2,0 \leq y \leq 1,2 y \leq x } & { \text 0, { elsewhere. } } \end{array} \right.$

Solving (a):

Find k

To solve for k, we use the definition of joint probability function:

$\int\limits^a_b \int\limits^a_b {f(x,y)} \, = 1$

Where

${ 0 \leq x} \leq 2,0 \leq y \leq 1,2 y \leq x }$

Substitute values for the interval of x and y respectively

So, we have:

$\int\limits^2_{0} \int\limits^{x/2}_{0} {k\ dy\ dx} \, = 1$

Isolate k

$k \int\limits^2_{0} \int\limits^{x/2}_{0} {dy\ dx} \, = 1$

Integrate y, leave x:

$k \int\limits^2_{0} y {dx} \, [0,x/2]= 1$

Substitute 0 and x/2 for y

$k \int\limits^2_{0} (x/2 - 0) {dx} \,= 1$

$k \int\limits^2_{0} \frac{x}{2} {dx} \,= 1$

Integrate x

$k * \frac{x^2}{2*2} [0,2]= 1$

$k * \frac{x^2}{4} [0,2]= 1$

Substitute 0 and 2 for x

$k *[ \frac{2^2}{4} - \frac{0^2}{4} ]= 1$

$k *[ \frac{4}{4} - \frac{0}{4} ]= 1$

$k *[ 1-0 ]= 1$

$k *[ 1]= 1$

$k = 1$

Solving (b): $P(x > 3y)$

We have:

$f(x,y) = k$

Where $k = 1$

$f(x,y) = 1$

To find $P(x > 3y)$ , we use:

$\int\limits^a_b \int\limits^a_b {f(x,y)}$

So, we have:

$P(x > 3y) = \int\limits^2_0 \int\limits^{y/3}_0 {f(x,y)} dxdy$

$P(x > 3y) = \int\limits^2_0 \int\limits^{y/3}_0 {1} dxdy$

$P(x > 3y) = \int\limits^2_0 \int\limits^{y/3}_0 dxdy$

Integrate x leave y

$P(x > 3y) = \int\limits^2_0 x [0,y/3]dy$

Substitute 0 and y/3 for x

$P(x > 3y) = \int\limits^2_0 [y/3 - 0]dy$

$P(x > 3y) = \int\limits^2_0 y/3\ dy$

Integrate

$P(x > 3y) = \frac{y^2}{2*3} [0,2]$

$P(x > 3y) = \frac{y^2}{6} [0,2]\\$

Substitute 0 and 2 for y

$P(x > 3y) = \frac{2^2}{6} -\frac{0^2}{6}$

$P(x > 3y) = \frac{4}{6} -\frac{0}{6}$

$P(x > 3y) = \frac{4}{6}$

$P(x > 3y) = \frac{2}{3}$

8 0

2 years ago

Solve for X. X/8 = 3 3/4 <br> A. 30 <br> B. 24 3/4 <br> C.120 <br> D.15/32

Feliz [49]

X / 8 = 3.75
X = 3.75 * 8
X = 30

6 0

3 years ago

Thirty children from an after-school club went to the matinee. This is 20% of the children in the club. How many children are in

Setler [38]

Answer:

Step-by-step explanation:

20%=30

x by 5 to get 100%

100%=150

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Theresa earned scores of 88 points, 84 points, 88 points, and 91 points on four tests. What is the lowest score she can get on t

Yanka [14]

So u will do 88+84=172+88=260+91=351 and that is all four tests added up now u have to divide the answer by 4 because it was four tests averages
351/4=87.75 wich is aproxamately 88
so with all four of them added wich is 351 u will add the answer choices so 351+96=447/5=89.4 wich is aproxamately 89
351+97=448/5=89.6 wich is aproxamately 90
351+98=449/5=89.8 wich is aproxamately 90
351+99=450/5=90
so i would say that 99 points is the one she needs to score because it isnt asking for aproxamately
so it is 99 points

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2 years ago

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