Answer:
We cannot infer at the 10% significance level that the assumption of ski centers is wrong
Step-by-step explanation:
The null hypothesis for this question can be stated as
Null hypothesis H0: =4
Alternate hypothesis Ha:
The test is two tailed
Standard Deviation –
= 2
z=(4.84-4)/(2/sqrt(63))
=3.33
Z(0.1/2)=1.645 is less than Z =3.334
Hence, we will reject H0
Hence, the average growth skier ski’s four times a year is not true
9514 1404 393
Answer:
- annually: 9.01 years
- monthly: 8.69 years
- daily: 8.67 years
- continuously: 8.66 years
Step-by-step explanation:
For interest compounded in discrete intervals, the formula is ...
A = P(1 +r/n)^(nt)
We want to find t for P=1 and A=2, so we have ...
2 = (1 +r/n)^(nt)
ln(2) = nt·ln(1+r/n)
t = ln(2)/(n·ln(1+r/n))
A table of values for r=0.08 is attached.
__
For continuous compounding, the formula is ...
A = Pe^(rt)
t = ln(A/P)/r = ln(2)/0.08 ≈ 8.66434 . . . . years
__
- annually: 9.01 years
- monthly: 8.69 years
- daily: 8.67 years
- continuously: 8.66 years
Answer:
a) (1215, 1297)
b) (1174, 1338)
c) (1133, 1379)
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 1256
Standard Deviation, σ = 41
Empirical Rule:
- Also known as 68-95-99.7 rule.
- It states that almost all the data lies within three standard deviation for a normal data.
- About 68% of data lies within 1 standard deviation of mean.
- About 95% of data lies within two standard deviation of mean.
- About 99.7% of data lies within 3 standard deviation of mean.
a) range of years centered about the mean in which about 68% of the data lies

68% of data will be found between 1215 years and 1297 years.
b) range of years centered about the mean in which about 95% of the data lies

95% of data will be found between 1174 years and 1338 years.
c) range of years centered about the mean in which about all of the data lies

All of data will be found between 1133 years and 1379 years.
Answer:
What's the question?
Step-by-step explanation:
Okay so basically when two people answer your questions it should give you the option to give brainliest otherwise sometimes it takes a few days to give it to someone. And for your question does it give any number options.?
Edit: f(-1)= 1 then f(1)= -10.