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dimulka [17.4K]

3 years ago

8

On spring break Mirna went to Florida. she collected 60 shells. The following set of data shows the weight of each seashell in o

unces. 16, 17, 13, 13, 15
which two measures are equal to 12

mean

median

mode

1 answer:

Volgvan3 years ago

6 0

i say 2 16's :) it may be wrong

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Please help i know it a lot but please

blsea [12.9K]

Answer:

I have no clue

Step-by-step explanation:

I'm in middle school I don't know

6 0

2 years ago

Clara simplifies {8b-4r}- {2b-r} and says the result is 6b-5r. What error did Clara make?

Nady [450]

She regrouped the numbers instead of multiplying like 8b(2b-r) -4r(2b-r).

8 0

3 years ago

Read 2 more answers

In triangle ABC, a = 9, c = 5, and B = 120°. Find b2.

anygoal [31]

Answer:

(D) $b^2=151$

Step-by-step explanation:

Given: In triangle ABC, a=9, c=5 and ∠B=120°.

To find: The value of $b^2$ .

solution: It is given that In triangle ABC, a=9, c=5 and ∠B=120°.

Now, using the law of cosines, we get

$b^2=a^2+c^2-2(a)(c)cosB$

Substituting the given values, we get

$b^2=9^2+5^2-2(9)(5)cosB$

$b^2=81+25-90(\frac{-1}{2})$

$b^2=81+25+45$

$b^2=151$

which is the required value of $b^2$ .

Therefore, option D is correct.

3 0

3 years ago

The coordinates of one vertex of this triangle are (–2, 2). If the triangle is translated 3 units to the left and 5 units down,

Romashka-Z-Leto [24]

Answer: (-5,-3)

Step-by-step explanation:

first you must know left and right is the x-axis while you and down is 4-axis, down and left is subtraction, right and up is addition

so 3 units left would affect x axis therefor subtracting 3 from -2 which is -5

now 5 units down would be the y-axis and subtracting, 2-5= -3

finally your answer will be (-5,-3)

7 0

3 years ago

Find how many solutions there are to the given equation that satisfy the given condition.

den301095 [7]

Answer:

17550 solutions

Step-by-step explanation:

Given that:

y1 +y2+y3+y4=27

where;

(yi ≥ 0 and yi $\epsilon$ $\mathbb {Z}$ )

The no. of a nonnegative integer determines the number of ways to choose 27 objects from (4) distinct objects with repetition regardless of the order.

i.e

$\bigg(^{27}_{4} \bigg)$

∴

The number of nonnegative integer solution is $\bigg(^{27}_{4} \bigg)$

$= \dfrac{27!}{4!(27-4)!}$

$= \dfrac{27!}{4!(23)!}$

$= \dfrac{27\times 26\times 25\times 24 \times 23 !}{4\times 3\times 2\times 1(23)!}$

$= \dfrac{27\times 26\times 25\times 24 }{4\times 3\times 2\times 1}$

$= \dfrac{421200}{24}$

= 17550 solutions

7 0

3 years ago