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Svetllana [295]
2 years ago
6

What would the height need to be for this curve to be a

Mathematics
1 answer:
antiseptic1488 [7]2 years ago
6 0

Answer: A

Step-by-step explanation:

The total area would have to be 1, so (1/2)(5)(height)=1

2.5height = 1

height = 1/2.5 = 2/10 = 1/5

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Answer:

\dfrac{2s^3+136}{s}

Step-by-step explanation:

Let the side length of the square base =s feet

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Given that the volume of the box = 34$ ft^3

Volume of the box =s^2h

Then:

s^2h=34$ ft^3\\$Divide both sides by s^2\\h=\dfrac{34}{s^2}

Surface Area of a Rectangular Prism =2(lb+bh+lh)

Since we have a square base, l=b=s feet

Therefore:

Surface Area of our closed box= 2(s^2+sh+sh)

S$urface Area= 2s^2+4sh\\Recall: h=\dfrac{34}{s^2}\\$Surface Area= 2s^2+4s\left(\dfrac{34}{s^2}\right)\\=2s^2+\dfrac{136}{s}\\$Surface Area in terms of length only=\dfrac{2s^3+136}{s}

7 0
3 years ago
Help<br> Help<br> Helppppppppp<br><br> Help<br> Help<br> Help
Eva8 [605]

Answer:

164 Cm^3

Step-by-step explanation:

Solution

V=

3

3

2

a

2

h

=

3

3

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7

≈

163.6788

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