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Anna007 [38]
3 years ago
6

What is the shortest, abbreviated version of the copy running-config startup-config command?

Computers and Technology
1 answer:
Juliette [100K]3 years ago
5 0

The answer is cop r s

The copy running-config startup-config command is a CISCO command used to back up the running config file to NVRAM. This ensures that once you have completed the basic configuration of a router or a switch, the changes made are not lost if the system loses power or is rebooted.

 

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Sedaia [141]

the answer is D Voice commands

8 0
3 years ago
I need help here thanks forever who helps
lubasha [3.4K]

Answer:

the horse, the man, and the cactus

Explanation:

The horse is running

The man got slung off the horse, so its in motion

The cactus is flying everywhere from the horse.

3 0
2 years ago
4
Nataly_w [17]

Answer:

5 hours 25 minutes

Explanation:

It takes 25 minutes to finish a hole

It takes 25*13 minutes to finish 13 holes

325 minutes is require to finish 13 holes

Convert 325 minutes to hours and minutes by dividing it by 60

=5 5/12 hours

Convert 5/12 hours to minutes by multiplying by 60

=25 minutes

The answer is 5 hours 25 minutes

5 0
3 years ago
Which automatic startup option should you choose when windows' startup fails immediately after installing a new driver but befor
Luda [366]

Answer:

last known good configuration

Explanation:

If you're having difficulties starting Windows, the Last Known Good Configuration, or LKGC for short, is a technique to get it started. It loads the drivers and registry data from the last time you began and shut down your computer successfully.

3 0
2 years ago
How many bits can a memory chip with the below configuration support? For full credit, show how you got the answer.
tatiyna

Answer:

Total Memory= 4 KB = 4096 bytes = 32768 bits

Explanation:

<em><u>1. Data lines are 8 From D0 to D7</u></em>

so

Total memory at single address locations is 8 bits.

<em><u>2. Address lines are 12 (A0 to A11)</u></em>

There are 12 address lines but 3 out 12 are for selction of chip or memory bank.

so only 9 pins are there to address the locations on one chip.

Total No. of address locations on single chip = 2^9 = 512 locations

as 1 location is 1 byte so total memory of single chip is 512 bytes.

<u><em>3. Total Memory Bank </em></u>

There are total 3 selection pins for memory bank.

so

Total chips = 2^3 = 8.

<em><u>4. Total Memory </u></em>

Total size of 1 chip = 512 bytes

Total size of 8 chip = 8x512 bytes = 4096 bytes = 4096/1024 kb = 4 kb

<em>So total memory of system is 4 Kb = 4096 bytes = 32768 bits</em>

5 0
3 years ago
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