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Mashcka [7]
2 years ago
10

Explain why sound is more clear at night than the day​

Physics
1 answer:
meriva2 years ago
5 0

because of god we can hear better at night.

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What is the resultant of a pair of one pound forces at right angles to each other?
OleMash [197]

Answer:

F_R=\sqrt{2} \ pound.force

Explanation:

Given that there are two force of 1 pound each at right angles to each other.

The from the vector law of addition:

F_R=\sqrt{F_1^2+F_2^2}

where:

F_R= resultant force

F_1\ \&\ F_2 be the two of the forces to be added.

F_R=\sqrt{1^2+1^2}

F_R=\sqrt{2} \ pound.force

8 0
3 years ago
Jerusha and anavi are working very hard to tend their organic veggie garden when jerusha sees a bunny nibbling on a tender letuc
zubka84 [21]

Answer:

Explanation:

Given:

Initial Velocity, u = 0 km/s (at rest)

Final Velocity, v = 16 km/s

Time taken, t = 3 sec

acceleration, a = (v - u)/t

= (16 - 0)/3

= 5.33 km/s^2

8 0
3 years ago
Find the three longest wavelengths (call them λ1, λ2, and λ3) that "fit" on the string, that is, those that satisfy the boundary
zepelin [54]
If you have a string that is fixed on both ends the amplitude of the oscillation must be zero at the beginning and the end of the string. Take a look at the pictures I have attached. It is clear that  our fundamental harmonic will have the wavelength of:
\lambda_1=\frac{L}{2}
All the higher harmonics are just multiples of the fundamental:
\lambda_n=n\lambda_1\\ \lambda_n=n\frac{L}{2}
Three longest wavelengths are:
n=3; \lambda_3=\frac{3L}{2}\\
n=2; \lambda_2=L\\
n=1; \lambda_=\frac{L}{2}\\


6 0
3 years ago
The magnitude of a negative of a vector is negative. O True O False
Paha777 [63]

Answer:

The given statement is false.

Explanation:

For any negative vector

\overrightarrow{r}=-x\widehat{i}-y\widehat{j}

The magnitude of the vector is given by

|r|=\sqrt{(-x)^{2}+(-y)^{2}}\\\\|r|=\sqrt{x^2+y^2}

As we know that square root of any quantity cannot be negative thus we conclude that the right hand term in the above expression cannot be negative hence we conclude that magnitude of any vector cannot be negative.

8 0
3 years ago
The scientific unit of force is the _________.
Ber [7]
The correct answer is C
5 0
3 years ago
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