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leva [86]
4 years ago
12

You feel a static electric shock when free electrons build up on your body then you touch a

Physics
1 answer:
Arlecino [84]4 years ago
6 0
Unit: 10 TEST
4. A- charger
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If Jerome is swinging on a rope and transferring energy from gravitational potential energy to kinetic energy, ________ is being
Ipatiy [6.2K]

Explanation:

A force that leads to movement of an object is known as work.

The energy present in an object due to its position in a gravitational field is known as gravitational potential energy.

Kinetic energy is the energy obtained by an object due to its motion.

For example, when Jerome is swinging on a rope then there occurs movement in the swing due to which the swing has kinetic energy.

Since, a force has been applied on the swing to make it move. Hence, a work is also done.

Therefore, we can conclude that if Jerome is swinging on a rope and transferring energy from gravitational potential energy to kinetic energy, work is being done.

3 0
4 years ago
Read 2 more answers
A bullet of mass m and speed v is fired at, hits and passes completely through a pendulum bob of mass M on the end of a stiff ro
dexar [7]

Required value of initial speed of the bullet be ( 4M/m)√(gL).

Given parameters:

Mass of the bullet =m.

Mass of the bob of the pendulum = M.

speed of the bullet before collision = v

Speed of the bullet after collision = v/2.

Length of the pendulum stiff rod = L.

Let speed transmitted to the pendulum be u.

Using principle of conservation of momentum:

mv = Mu + mv/2

⇒ Mu = mv/2

⇒ u = (m/M)v/2

We know that: to make the bob over the top of the trajectory without falling backward in its circular path, required speed be = √(4gL). [ where g = acceleration due to gravity]

To be minimum initial speed the bullet must have in order for the pendulum bob to just barely swing through a complete vertical circle:

u = √(4gL)

⇒  (m/M)v/2 = √(4gL)

⇒ v =( 4M/m)√(gL).

Hence, minimum required  speed of the bullet be ( 4M/m)√(gL).

Learn more about speed here:

brainly.com/question/28224010

#SPJ1

7 0
1 year ago
A _____ is used in a motor to switch the direction of the magnetic field created by the current.
insens350 [35]

Answer:

A _commutator_ is used in a motor to switch the direction of the magnetic field created by the current.

The rotating part of a motor that holds the electromagnets is called the __armature___.

Electric current passes through the _brushes_ and into the electromagnets in an electric motor.

A motor turns _electrical_ energy into _mechanical_ energy.

Explanation:

A commutator, which is a split ring rotary switching device, reverses the direction of the current between the external circuit and the rotor. Reversing the current reverses the magnetic field.

The armature comprises the rotating part of the motor and the electromagnets

A brush is the electrical contact for conducting current through the moving and stationary parts of an electric motor

An electric motor turns electrical energy into mechanical energy.

8 0
4 years ago
ANSWER FAST!!!!
Amiraneli [1.4K]

Power = (voltage) x (current)

Power = (240 volts) x (4 Amp)

Power = 960 watts

4 0
4 years ago
Would the frequency of the angular simple harmonic motion (SHM) of the balance wheel increase or decrease if the dimensions of t
storchak [24]

Answer:

Yes the frequency of the angular simple harmonic motion (SHM) of the balance wheel increases three times if the dimensions of the balance wheel reduced to one-third of original dimensions.

Explanation:

Considering the complete question attached in figure below.

Time period for balance wheel is:

T=2\pi\sqrt{\frac{I}{K}}

I=mR^{2}

m = mass of balance wheel

R = radius of balance wheel.

Angular frequency is related to Time period as:

\omega=\frac{2\pi}{T}\\\omega=\sqrt{\frac{K}{I}} \\\omega=\sqrt{\frac{K}{mR^{2}}

As dimensions of new balance wheel are one-third of their original values

R_{new}=\frac{R}{3}

\omega_{new}=\sqrt{\frac{K}{mR_{new}^{2}}}\\\\\omega_{new}=\sqrt{\frac{K}{m(\frac{R}{3})^{2}}}\\\\\omega_{new}={3}\sqrt{\frac{K}{mR^{2}}}\\\\\omega_{new}={3}\omega

5 0
3 years ago
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