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BigorU [14]
2 years ago
11

you have a 200 kg bag being lifted with a block and tackle. If you pull with 100 newtons what is the MA of the system?

Physics
2 answers:
Korvikt [17]2 years ago
7 0

Answer:

The mechanical advantage of the system is equal to 19.62

Explanation:

The ratio of the force produced by a machine to the force applied to it is called mechanical advantage. In other words it is the ratio of output force to the input force.

In this problem mass=200kg

applied force=100N  

input force=100N

output force=mg=200 \times 9.8=196N.

mechanical advantage MA= \frac{1960}{100}=19.6

It gives an idea about the efficiency of a mechanical device. It is indeed a measure of force amplification. In block and tackle system an assembly of ropes and pulleys is used to lift loads. When the moving block is supported by a  greater  number of rope sections the force amplification will be more.

charle [14.2K]2 years ago
4 0

Answer:

19.6

Explanation:

MA=Ouput/Input

To get output value multiply; 200 (which is the mass) * 9.8 (which is gravity)

So, 200*9.8=1960N

Input is 100 because that is the force you are putting into the bag

Back to our formula MA=Output/Input, enter in our values...

MA=1960/100

Now divide 1960/100=19.6

MA=19.6

(no units; they cancel out).

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A 100 kg bag of sand has a weight on 100 N. When dropped its acceleration is what?
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Answer:

The acceleration of the bag of sand is 1\ m/s^2.

Explanation:

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F =ma

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g=\dfrac{F}{m}\\\\g=\dfrac{100}{100}\\\\g=1\ m/s^2

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3 years ago
Type the correct answer in the box. Round your answer to the nearest whole number. Calculate the man’s mass. (Use PE = m × g × h
Blababa [14]

Answer:

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Explanation:

The change in potential energy of the man is given by:

\Delta U = mg \Delta h

where

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In this problem, we have:

\Delta U=4620 J is the gain in potential energy

g = 9.8 m/s^2 is the gravitational acceleration

\Delta h=8.4 m is the change in height

Re-arranging the equation and substituting the numbers, we find the mass:

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6 0
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At one instant, a 17.0-kg sled is moving over a horizontal surface of snow at 4.10 m/s. After 6.15 s has elapsed, the sled stops
jasenka [17]

Answer:

force = 11.33 kg-m/s^{2}

Explanation:

given data:

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from newton second law of motion

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F = \frac{P_{1}-P_{2}}{T}

Kgm/s^2

F = \frac{69.7-0}{6.15}= 11.33[tex]kg-m/s^{2}[/tex]

8 0
3 years ago
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