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3 years ago

The atmosphere of earth does not escape into the space but remains attached to earth's surface why??

1 answer:

7 0

Just like any other gas or mixture of gases, the gas molecules are
zipping around in all different directions and with a whole range of
different speeds.

Those that happen to be moving at a speed greater than the Earth's
"escape velocity", AND are pointed away from Earth, AND don't hit
any other molecules before they escape, are lost.

With the combination of Earth's escape velocity, and the temperatures,
thickness, and density of the atmosphere, that process happens slowly
enough to have maintained an atmosphere around this planet until now.

Personally, I hope it hangs around for a while longer. But with the constant
increase in temperature that's been going on, you never know . . .

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PLEASE HELP ASAP!!!!!

Damm [24]

I believe the answer is resonance

6 0

3 years ago

Consider Compton Scattering with visible light.A photon with wavelength 500nm scatters backward(theta=180degree) from a free ele

JulijaS [17]

Answer: $4.86(10)^{-12}m$

Explanation:

The Compton Shift $\Delta \lambda$ in wavelength when photons are scattered is given by the following equation:

$\Delta \lambda=\lambda' - \lambda_{o}=\lambda_{c}(1-cos\theta)$ (1)

Where:

$\lambda'=500 nm=500(10)^{-9} m$ is the wavelength of the scattered photon

$\lambda_{o}$ is the wavelength of the incident photon

$\lambda_{c}=2.43(10)^{-12} m$ is a constant whose value is given by $\frac{h}{m_{e}.c}$ , being $h=4.136(10)^{-15}eV.s$ the Planck constant, $m_{e}$ the mass of the electron and $c=3(10)^{8}m/s$ the speed of light in vacuum.

$\theta=180\°$ the angle between incident phhoton and the scatered photon.

$\Delta \lambda=2.43(10)^{-12} m (1-cos(180\°))$ (2)

$\Delta \lambda=4.86(10)^{-12}m$ (3) This is the shift in wavelength

5 0

3 years ago

What voltage can be applied by a resistor<br><br>190 Ω and 100 A?

Anettt [7]

Answer:

V=IR

V=100×190

=19000 V

4 0

3 years ago

Sin133+sin 133 value plz give answer

mamaluj [8]

Its 1.73793151243 as a whole but if rounded it is 1.74

3 0

4 years ago

Magnus has reached the finals of a strength competition. In the first round, he has to pull a city bus as far as he can. One end

ozzi

Answer:

The total work that the rope does to Mangnus is - 5780 Jules.

Explanation:

By definition, the work is defined as:

$W=F.d$

Where F and d are the force and the total displacement. Note that in the definition the product is a scalar product since F and d are both vectors.

Take into account that according to third Newton's law the force that the rope does to Magnus is opposite to the force that Magnus does to the rope, therefore the scalar product will be negative due the rope's force goes against to Magnus displacement.

For calculating the work, we take 2500 N as the value for the force and 2.312 meters as the value for the displacement:

$W=-2500 N * 2.312 m$

$W=-5780 Nm = -5780 J$

7 0

3 years ago