Answer:
The spring constant of this spring is 200 N/m.
Explanation:
Given:
Original unstretched length of the spring (x₀) = 10 cm =0.10 m [1 cm =0.01 m]
Stretched length of the spring (x₁) = 18 cm = 0.18 cm
Force acting on the spring (F) = 16 N
Spring constant of the spring (k) = ?
First let us find the change in length of the spring or the elongation caused in the spring due to the applied force.
So, Change in length = Final length - Initial length
Now, restoring force acting on the spring is directly related to its elongation or compression as:
Rewriting in terms of 'k', we get:
Now, plug in the given values and solve for 'k'. This gives,
Therefore, the spring constant of this spring is 200 N/m.
Answer
given,
difference between the two consecutive maximum
λ = 0.870 - 0.540
λ = 0.33 m
speed of sound = 340 m/s
b) frequency of the sound
v = f x λ
340 = f x 0.33
f = 1030.3 Hz
a) phase difference
the expression of phase difference is given by
now,
Answer:
speed of car = 95 km/h
speed of truck = 75 km/h
relative speed of car with respect to truck = 95 - 75 = 20 km/h
now we will convert it into m/s
now time to cross the truck will be given as
time = 19.8 s
so it will take 19.8 s to cross the truck
Explanation:
Explanation:
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