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7nadin3 [17]
3 years ago
5

A point charge of 8.0 C is placed 0.050 m from a rod that has an electric field of 1.5 × 103 N/C. What is the electric potential

energy of the point charge? 6.0 × 10-4 J 2.4 × 10-1 J 6.0 × 102 J 2.4 × 105 J
Physics
2 answers:
Olenka [21]3 years ago
8 0
We can solve the equation using the formula for electric potential in the electric of a point charge such as shown below:
V = (K*Q)/D

We are given with some values such as:
K = 1.5 x10^3
Q=8.0 C
D=0.05 meters

Solving for V:
V = (8.0 * 1.5x10^3)/0.05
V = 2.4 x 10^ J


Digiron [165]3 years ago
3 0

on edge the answer is 6.0 × 10^-4 J

just took the test

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The Special Olympics raises money through "plane pull" events in which teams of 25 people compete to see who can pull a 74,000 k
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Answer:

28716.4740661 N

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Explanation:

m = Mass of plane = 74000 kg

s = Displacement = 3.7 m

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t = Time taken = 6.1 s

u = Initial velocity = 0

v = Final velocity

s=ut+\frac{1}{2}at^2\\\Rightarrow 3.7=0\times 6.1+\frac{1}{2}\times a\times 6.1^2\\\Rightarrow a=\frac{3.7\times 2}{6.1^2}\\\Rightarrow a=0.198871271164\ m/s^2

Force is given by

F=ma+f\\\Rightarrow F=74000\times 0.198871271164+14000\\\Rightarrow F=28716.4740661\ N

The force with which the team pulls the plane is 28716.4740661 N

v=u+at\\\Rightarrow v=0+0.198871271164\times 6.1\\\Rightarrow v=1.2131147541\ m/s

The speed of the plane is 1.2131147541 m/s

Kinetic energy is given by

K=\dfrac{1}{2}mv^2\\\Rightarrow K=\dfrac{1}{2}\times 74000\times 1.2131147541^2\\\Rightarrow K=54450.9540448\ J

Work done is given by

W=Fs\\\Rightarrow W=28716.4740661\times 3.7\\\Rightarrow W=106250.954045\ J

The fraction is given by

\dfrac{54450.9540448}{106250.954045}=0.512474965841

The teams 51.2474965841% of the work goes to kinetic energy of the plane.

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