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deff fn [24]
2 years ago
15

Cindy is baking a 2-layer cake. The top layer has a diameter of 8 inches and the bottom layer has a diameter of 10 inches. What

is the difference in area between the top surfaces of the two cakes? Use 3. 14 for π
Mathematics
1 answer:
Alenkinab [10]2 years ago
5 0

The difference in area between the top surfaces of the two cakes is 28.26 inches²

<h3>Area of a circle</h3>
  • area = πr²

where

r = radius

Therefore,

area of top layer = πr²

d = 2r

r = d / 2

r = 8 / 2

r = 4 inches

area of top layer = 3.14 × 4²

area of top layer = 3.14 × 16

area of top layer = 50.24 inches²

area of the bottom layer = πr²

r = 10 / 2 = 5 inches

area of the bottom layer = 3.14 × 5²

area of the bottom layer = 3.14 ×25

area of the bottom layer = 78.5 inches²

Difference in area between the top surfaces of the two cakes can be found as follows:

  • 78.5 - 50.24 = 28.26 inches²

learn more on circle here: brainly.com/question/10264279

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PLZ help i do know the answer to this already from another brainly question but i just would like to understand how its solved s
amm1812

Answer:

  • 66.56 cm

Step-by-step explanation:

<u>The figure consist of:</u>

  • 1. A rectangle with sides 10 cm and 17 cm
  • 2. A quarter circle

<u>The perimeter is:</u>

  • P = 1/4C + 2*10 + 17 + (17 - 8) + 8
  • P = 1/4*2*3.14*8 + 54 = 66.56 cm
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2 years ago
If the side length is 6. cm, then the area is ______cm2 ?
ArbitrLikvidat [17]

Answer:

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Step-by-step explanation:

tep-by-Step:

Start with the formula:

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Don't forget: a2 = a × a (a squared).

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Area = 6^2 = 6 × 6 = 36 cm2

Answer:

The area of the square with sides of length 6 cm is 36 cm2.

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