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2 years ago

12

… I don’t know what to say but the question on the photo I sent pls help me it’s due in 30 MINUTES!!!

1 answer:

ycow [4]2 years ago

3 0

Answer: Hope this all helps :)

Step-by-step explanation:

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3 3/4 times 2 1/3 times 7/2<br><br><br><br><br><br> I really need some help on this

MrRa [10]

<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>:</em><em>)</em>

3 0

3 years ago

Read 2 more answers

What is the range of the function g(x)= x-12 -2

FinnZ [79.3K]

Answer:

all real numbers

Step-by-step explanation:

8 0

2 years ago

Please I need help with differential equation. Thank you

Inga [223]

1. I suppose the ODE is supposed to be

$\mathrm dt\dfrac{y+y^{1/2}}{1-t}=\mathrm dy(t+1)$

Solving for $\dfrac{\mathrm dy}{\mathrm dt}$ gives

$\dfrac{\mathrm dy}{\mathrm dt}=\dfrac{y+y^{1/2}}{1-t^2}$

which is undefined when $t=\pm1$ . The interval of validity depends on what your initial value is. In this case, it's $t=-\dfrac12$ , so the largest interval on which a solution can exist is $-1\le t\le1$ .

2. Separating the variables gives

$\dfrac{\mathrm dy}{y+y^{1/2}}=\dfrac{\mathrm dt}{1-t^2}$

Integrate both sides. On the left, we have

$\displaystyle\int\frac{\mathrm dy}{y^{1/2}(y^{1/2}+1)}=2\int\frac{\mathrm dz}{z+1}$

where we substituted $z=y^{1/2}$ - or $z^2=y$ - and $2z\,\mathrm dz=\mathrm dy$ - or $\mathrm dz=\dfrac{\mathrm dy}{2y^{1/2}}$ .

$\displaystyle\int\frac{\mathrm dy}{y^{1/2}(y^{1/2}+1)}=2\ln|z+1|=2\ln(y^{1/2}+1)$

On the right, we have

$\dfrac1{1-t^2}=\dfrac12\left(\dfrac1{1-t}+\dfrac1{1+t}\right)$

$\displaystyle\int\frac{\mathrm dt}{1-t^2}=\dfrac12(\ln|1-t|+\ln|1+t|)+C=\ln(1-t^2)^{1/2}+C$

So

$2\ln(y^{1/2}+1)=\ln(1-t^2)^{1/2}+C$

$\ln(y^{1/2}+1)=\dfrac12\ln(1-t^2)^{1/2}+C$

$y^{1/2}+1=e^{\ln(1-t^2)^{1/4}+C}$

$y^{1/2}=C(1-t^2)^{1/4}-1$

I'll leave the solution in this form for now to make solving for $C$ easier. Given that $y\left(-\dfrac12\right)=1$ , we get

$1^{1/2}=C\left(1-\left(-\dfrac12\right)^2\right))^{1/4}-1$

$2=C\left(\dfrac54\right)^{1/4}$

$C=2\left(\dfrac45\right)^{1/4}$

and so our solution is

$\boxed{y(t)=\left(2\left(\dfrac45-\dfrac45t^2\right)^{1/4}-1\right)^2}$

3 0

3 years ago

Solve using the appropriate method a-3b=33 <br> b+6=2a

Varvara68 [4.7K]

Answer:

1= -6b=a

Step-by-step explanation:

a-3b=33b+6=2a

+3b +3b

a=36b+6=2a

-6 -6

a -6=36b=2a

---------------

-6 -6

a= -6b=2a

This is the work and the answer

6 0

3 years ago

A 4.3 ounce tomato has about 24 calories. How many calories are in one ounce ?

mafiozo [28]

Answer: approximately 5.5814 calories

==================================

We start off with this ratio

4.3 ounces : 24 calories

Divide both parts of the ratio by 4.3 so that we end up with 1 ounce on the left side

4.3 ounces : 24 calories

4.3/4.3 ounces : 24/4.3 calories

1 ounce : 5.5814 calories

This value is approximate to four decimal places.

7 0

3 years ago