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2 years ago

14

Joe bought a computer three years ago for $6570. He assumed the value of the computer would depreciate at a rate of 6 3\4% per m

onth. What is the value of the computer at the end of three years?

2 answers:

Valentin [98]2 years ago

7 0

Answer:

305?

Step-by-step explanation:

if wrong sorry font be angry

zimovet [89]2 years ago

5 0

530.791093416 or 530.79$

Step-by-step explanation:

6570-6.75^36=530.791093416 or 530.79$

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Find the prime factorizations foor the following numbers 36 and 84

Varvara68 [4.7K]

Answer:

36 = 2² * 3²
84 = 2² * 3 * 7

Explanation:

Pf of 36 = 2 * 2 * 3 * 3 which then becomes 2 (to the power of 2) times 3 (to the power of 2)

Pf of 84 = 2 * 2 * 3 * 7 which then becomes 2 (to the power of 2) * 3 * 7

If this helps it would be greatly appreciated if you thanked me.

6 0

3 years ago

7.109) The leading brand of dishwasher detergent has a 30% market share. A sample of 25 dishwasher detergent customers was taken

Rina8888 [55]

Answer:

0.9021 = 90.21% probability that 10 or fewer customers choose the leading brand

Step-by-step explanation:

For each customer, there are only two possible outcomes. Either they choose the leading brand, or they do not. The probability of a customer choosing the leading brand is independent of any other customer, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The leading brand of dishwasher detergent has a 30% market share.

This means that $p = 0.3$

A sample of 25 dishwasher detergent customers was taken.

This means that $n = 25$

a. What is the probability that 10 or fewer customers choose the leading brand?

This is:

$P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{25,0}.(0.3)^{0}.(0.7)^{25} = 0.0001$

$P(X = 1) = C_{25,1}.(0.3)^{1}.(0.7)^{24} = 0.0014$

$P(X = 2) = C_{25,2}.(0.3)^{2}.(0.7)^{23} = 0.0074$

$P(X = 3) = C_{25,3}.(0.3)^{3}.(0.7)^{22} = 0.0243$

$P(X = 4) = C_{25,4}.(0.3)^{4}.(0.7)^{21} = 0.0572$

$P(X = 5) = C_{25,5}.(0.3)^{5}.(0.7)^{20} = 0.1030$

$P(X = 6) = C_{25,6}.(0.3)^{6}.(0.7)^{19} = 0.1472$

$P(X = 7) = C_{25,7}.(0.3)^{7}.(0.7)^{18} = 0.1712$

$P(X = 8) = C_{25,8}.(0.3)^{8}.(0.7)^{17} = 0.1651$

$P(X = 9) = C_{25,9}.(0.3)^{9}.(0.7)^{16} = 0.1336$

$P(X = 10) = C_{25,10}.(0.3)^{10}.(0.7)^{15} = 0.0916$

Then

$P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.0001 + 0.0014 + 0.0074 + 0.0243 + 0.0572 + 0.1030 + 0.1472 + 0.1712 + 0.1651 + 0.1336 + 0.0916 = 0.9021$

0.9021 = 90.21% probability that 10 or fewer customers choose the leading brand

3 0

3 years ago

HELP ME PLEASE!!!!<br> ΔAXY ~ ΔABC. What is the value of BC

emmasim [6.3K]

Answer:

BC = 28 $\frac{1}{3}$ ft

Step-by-step explanation:

Given that the triangles are similar then the ratios of corresponding sides are equal, that is

$\frac{AX}{AB}$ = $\frac{XY}{BC}$ , substitute values

$\frac{12}{20}$ = $\frac{17}{BC}$ ( cross- multiply )

12BC = 340 ( divide both sides by 12 )

BC = $\frac{340}{12}$ = $\frac{85}{3}$ = 28 $\frac{1}{3}$

6 0

3 years ago

2854 / 32<br><br> A. 89<br> B. 89 3/16<br> C. 89 5/16<br> D. 89 3/8

Marrrta [24]

Its b
2854/32 = 1427/16 = 89 3/16

7 0

3 years ago

Read 2 more answers

Greatest to least - 1/2, 3/5, 3/7

Natalka [10]

3/7, 3/5, 1/2 is the answer it starts from the lowest to the lagest

4 0

3 years ago