Answer:

Step-by-step explanation:
The exponential model for the population in t years after 2013 is given by:

In which P(0) is the population in 2013 and r is the growth rate.
In 2013, the moose population in a park was measured to be 5,100
This means that 
So

By 2018, the population was measured again to be 5,200.
2018 is 2018-2013 = 5 years after 2013.
So this means that
.
We use this to find r.







So the equation for the moose population is:

The next numbers are 32 and -64 the pattern multiplies by -2
Answer:
A. EG = √3 × FG
D. EG = √3/2 × EF
E. EF = 2 × FG
Step-by-step explanation:
∵ tan 60 = √3
∵ tan60 = EG/GF
∴ EG/GF = √3
∴ EG = √3 × GF ⇒ A
∵ m∠F = 60°
∵ sin60 = √3/2
∵ sin 60 = EG/EF
∴ √3/2 = EG/EF
∴ EG = √3/2 × EF ⇒ D
∵ cos60 = 1/2
∵ cos60 = GF/EF
∴ GF/EF = 1/2
∴ EF = 2 × GF ⇒ E
Answer:
Hey!!!!
the answers are 2, 6, 3, 12, 4, 1
Please read the explanation... it always helps..
Step-by-step explanation:
Alrighty... let's begin....
A factor is any number that you can multiply by another number to get a product
So choose the numbers you can mutiply by another number to get twelve... which are... 2, 6, 3, 12, 4, 1
if you are wondering why twelve well... 12 x 1 = 12
i hope this helps!!!!
Membership is discounted $2 for first month
c=cost of one month
d=discount=$2
x=# of months
xc - 2= total cost
x for 1 month is 1, c is always 12, -2 is constant
1 x(12) - 2=10 for first month
8 months
8c -2=total cost for 8 months
8 x 12 - 2= 94 for 8 months