To find midpoint, we find the average or median of the two x terms and the average of the two y terms to find the right coordinate point. In this case, the average of -2 and 6 is 2, and the mean of 4 and -4 is 0, so the new coordinate point is (2,0).
Answer:
(2,10) or x=2 y=10
Step-by-step explanation:
<em>1. Pick one of your equations and solve for a variable. I chose the first equation and solved for x.</em>
5x-2y=-10 (Move the -2y to the other side, you need to do the opposite so you add +2y to -10)
5x=2y-10 (Divide the 5 from the x)
x=2/5y-2
<em>2. Now take what you got for x and plug it into the x variable on the other equation.</em>
3(2/5y-2)+6y=66 (Multiply 3 by 2/5y and -2)
6/5y-6=6y=66 (Move the -6 to the other side and add 6/5y to 6y)
36/5y=72 (Since the number on the y is a fraction, you must do the opposite to the other side)
y=72/1 x 5/36 (Flip your fraction and multiply it by the 72)
y=10
<em>3. Now that you have one of the variables solved for, in order to get the other we must plug in what we have to the first equation.</em>
5x-2(10)=-10 (Multiple 2 by 10)
5x-20=-10 (Move -20 to the other side, since you do the opposite add +20 to the -10)
5x=10 ( Divide 10 by 5)
x= 2
<em>4. If needed, plug in the values of x and y to check your solution.</em>
Hope this could help! :)
I believe x is 0 because if we assume y and x are 0 then 0=0 and 0= 5 x 0
Step-by-step explanation:
The equation of a parabola with focus at (h, k) and the directrix y = p is given by the following formula:
(y - k)^2 = 4 * f * (x - h)
In this case, the focus is at the origin (0, 0) and the directrix is the line y = -1.3, so the equation representing the cross section of the reflector is:
y^2 = 4 * f * x
= 4 * (-1.3) * x
= -5.2x
The depth of the reflector is the distance from the vertex to the directrix. In this case, the vertex is at the origin, so the depth is simply the distance from the origin to the line y = -1.3. Since the directrix is a horizontal line, this distance is simply the absolute value of the y-coordinate of the line, which is 1.3 inches. Therefore, the depth of the reflector is approximately 1.3 inches.
