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SVEN [57.7K]
3 years ago
15

Find the area of the triangle ABC A(-6,2) B(3,2) c(-2,6) D (-2,2)

Mathematics
1 answer:
frez [133]3 years ago
6 0

Answer:

18 square units.

Step-by-step explanation:

Area of the triangle = ½*AB*CD

First of all, find the length of AB and CD using the distance formula, d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

A(-6, 2) => (x1, y1)

B(3, 2) => (x2, y2)

AB = \sqrt{(3 -(-6))^2 + (2 - 2)^2}

AB = \sqrt{(9)^2 + (0)^2} = \sqrt{81} = 9

CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

C(-2, 6) => (x1, y1)

D(-2, 2) => (x2, y2)

CD = \sqrt{(-2 -(-2))^2 + (2 - 6)^2}

CD = \sqrt{(0)^2 + (-4)^2} = \sqrt{16} = 4

AB = 9

CD = 4

Area of rectangle = ½*AB*CD = ½*9*4 = 9*2 = 18 square units.

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