Answer:
A. (-1, -16)
Step-by-step explanation:
Answer:
D. 2x²
Step-by-step explanation:
Ok, so the first thing to do is remember the first number in parentheses is x, and the second number is y.
You're trying to figure out which expression turns x into y in each set.
Just by plugging in the numbers into each expression I found that the answer is 2x².
I'll prove this starting with (1, 2).
1² = 1
2 x 1 = 2
So, y = 2x²!
Next, (2, 8).
2² = 4
2 x 4 = 8
So, y = 2x²!
I'm not going to demonstrate with the other two but I hope you understand. Just plug the values of x and y into the equation and see which is correct.
Answer: C. 3.2 × 10^4
Step-by-step explanation:
for this case the multiplication of the values with exponent are summed, as the exponent are the 6 and -3
6 - 3 = 3
this will be the exponent of the common value which is the 10.
after you only need to multiply 8 and 4 by separate the
8 * 4 = 32.
then we only need to place the values one by one
32 × 10^3
3 is the result of the sum of the exponent.
10 is the common value.
32 is the result of the product.
if we add another zero to the multiplication we get 3.2 and exponent finish with one more zero, then we get this result
3.2 × 10^4
because of that the C is the correct answer, keep in mind that the other answers do not apply correctly the rule of the exponent, because the rest of answer give us wrong answer with final result of the exponent.
Answer:
Per2 = 102.727 dm
Per1 = 123.272 dm
Step-by-step explanation:
We know that the area of similar triangles are related to the square of their perimeters.
This means that
(Per1^2)/(Per2^2) = Area1 / Area2
If we take the square root of the previous equation
(Per1)/(Per2) = 
(Per1)/(Per2) = 
(Per1)/(Per2) = 1.2
We also know that
Per1 + Per2 = 226 dm
So,
1.2*Per2 + Per2 = 226 dm
2.2*Per2 = 226 dm
Per2 = 102.727 dm
Per1 = 1.2*Per2 = 123.272 dm
It is not a function because it does not pass the vertical line test. For every x value there must be only 1 y value but this graph is not a function because there are 2 y values for every y value.