12:00 will have both hands pointing up
12:30 will have the straight line at the half past part but it will not be exactly on the 12
3:45 it will be past the 3 and exactly on 45 so it will not work
And 6:00 will be a straight line as one hand will be at the 12 and and it will be straight on the 6 as it is on the hour so the answer is d
The solutions to the given system of equations are x = 4 and y = -9
<h3>Simultaneous linear equations</h3>
From the question, we are to determine the solutions to the given system of equations
The given system of equations are
-8x-4y=4 --------- (1)
-5x-y=-11 --------- (2)
Multiply equation (2) by 4
4 ×[-5x-y=-11 ]
-20x -4y = -44 -------- (3)
Now, subtract equation (3) from equation (1)
-8x -4y = 4 --------- (1)
-(-20x -4y = -44) -------- (3)
12x = 48
x = 48/12
x = 4
Substitute the value of x into equation (2)
-5x -y = -11
-5(4) -y = -11
-20 -y = -11
-y = -11 + 20
-y = 9
∴ y = -9
Hence, the solutions to the given system of equations are x = 4 and y = -9
Learn more on Simultaneous linear equations here: brainly.com/question/26310043
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Answer:
(5,-2)
Step-by-step explanation:
6+4=10
10/2=5
-6+2=-4
-4/2=-2
Answer:
x = 12
Step-by-step explanation:
Recall: the secant-tangent rule states that when a secant and a tangent meet at an external point of a circle, the product of the secant and the external segment is equal to the square of the tangent segment
(x)(3) = 6² (secant-tangent rule)
3x = 36
Divide both sides by 3
3x/3 = 36/3
x = 12
Answer:
A
Step-by-step explanation:
